Answer:
DE = 13.4 cm (to 1 decimal place)
Step-by-step explanation:
Given: ABCD is a square
BC = AC = 12 cm (opposite sides of a square are congruent)
E is midpoint of BC (given)
BE = EC = 12/2 = 6 cm
CD = AB = 12 cm (opposite sides of a square are congruent)
angle ECD is a right angle (interior angles of a square are 90 deg.)
Consider right triangle ECD
DE = sqrt(EC^2+CD^2) ............. pythagorean theorem
= sqrt(6^2+12^2)
= sqrt ( 36+144 )
= sqrt (180)
= 2 sqrt(45)
= 13.416 (to three dec. places)
Answer
Step by step explanation
Add the numbers
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Move constant to right hand side and change it's sign
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Calculate the difference
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Hope I helped!
Best regards!!
Given:
Segment AC = 130 feet
Segment CD = 70 feet
I think that I'll be using the Pythagorean Theorem in finding the value of r. r will be the hypotenuse
Segment CE = (r - 70 feet)
r² = a² + b²
r² = 130² + (r-70)²
r² = 16,900 + (r-70)(r-70)
r² = 16,900 + r² - 70r - 70r + 4900
r² - r² + 140r = 16,900 + 4,900
140r = 21,800
r = 21,800/140
r = 155.71 feet
The radius of the circle is 155.71 feet.
The unit of measurement appropriate for this would be meters^2
Step-by-step explanation:
-9(-10-9)
90+81
171
hope it helps..
