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UkoKoshka [18]
3 years ago
15

How is finding the surface area of a three-dimensional figure related to the net of the figure?

Mathematics
2 answers:
andre [41]3 years ago
8 0

Answer:

(B)The surface area is equal to the area of its two-dimensional net.

Step-by-step explanation:

The surface area of a 3D object is the sum of the areas of the various sides that make up this figure. Essentially, if you unroll the object into its 2D net, then the area that this net covers will be the surface area.

Think about a cube, for example. It has 6 square sides, so its surface area is the sum of the areas of those squares. If we take the net of the cube, it's also 6 squares, and if we sum those together, we'll get the same answer.

Thus, the answer is B.

Oduvanchick [21]3 years ago
8 0

According to me, I think it will be option (b) The surface area is equal to the area of its two-dimensional net.

HOPE IT HELPS YOU

HAVE A GOOD DAY ❤️☺️

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12:1

Step-by-step explanation:

96/8 = 12

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What is the value of 1/2 x3 + 3.4y when x = 2 and y = 5<br> The X3 The 3 in that is Over X
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I think this is the answer. I might be wrong!
Have a great day! :D
5 0
3 years ago
The height "h" of a ball thrown straight up with a velocity of 88 ft/s is given by h = -16t^2 + 88t where "t" is the time it is
Dvinal [7]

By definition of the zeros of ta quadratic function,  for 5.5 seconds the ball is in the air before it hits the ground.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

That is, the zeros represent the roots of the polynomial equation that is obtained by making f(x)=0.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

<h3>Time the ball is in the air before it hits the ground</h3>

In this case, the height "h" of a ball thrown straight up with a velocity of 88 ft/s is given by h = -16t² + 88t, where "t" is the time it is in the air.

When the ball hits he ground, he height h has a value of zero. This is h=0. Replacing in the previous expression for the height you get:

0= -16t² + 88t

It can be solved by extracting the term "t" as a common factor:

0= t×(-16t + 88)

The Zero Product Principle says that if the product of two numbers is 0, then at least one of the factors is 0. Then:

t= 0

or

0= -16t + 88

Solving: -88= -16t

(-88)÷ (-16)=t

<u><em>5.5= t</em></u>

Finally, this means that for 5.5 seconds the ball is in the air before it hits the ground.

Learn more about the zeros of a quadratic function:

brainly.com/question/12649112

brainly.com/question/21320065

brainly.com/question/12037466

#SPJ1

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