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Natali [406]
3 years ago
7

3.8,3.789,3,3 41/50 from greastest to least

Mathematics
1 answer:
9966 [12]3 years ago
8 0
3   3.789   3.8    3 41/50
is least to greatest

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Find a point on the ellipsoid x2+y2+4z2=36x2+y2+4z2=36 where the tangent plane is perpendicular to the line with parametric equa
Anvisha [2.4K]

Answer:

A point on the ellipsoid is (-4,2,2) or (4,-2,-2)

Step-by-step explanation:

Given equation of ellipsoid f(x,y,z) :x^2+y^2+4z^2=36

Parametric equations:

x=-4t-1

y=2t+1

z=8t+3

Finding the gradient of function

\nabla f(x,y,z)=\\\nabla f(x,y,z)=

So, The directions vectors=(-4,2,8)

Now the line is perpendicular to plane when direction vector is parallel to the normal vector of line

\nablaf(x,y,z)=(2x,2y,8z)=\lambda(-4,2,8)

So, 2x=-4\lambda

\Rightarrow x=-2\lambda

2y=2\lambda\\\Rightarrow y=\lambda\\8z=8\lambda\\\Rightarrow z=\lambda

Substitute the value of x , y and z in the ellipsoid equation

(2\lambda)^2+(\lambda)^2+4(\lambda)^2=36\\9(\lambda)^2=36\\\lambda^2=4\\\lambda=\pm 2

With \lambda = 2

x=-2(2)=-4

y=2

z=2

With\lambda =- 2

x=-2(-2)=4

y=-2

z=-2

Hence a point on the ellipsoid is (-4,2,2) or (4,-2,-2)

7 0
3 years ago
Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma
Tanzania [10]

Answer:

step 2

Step-by-step explanation:

we have

x^{2} +10x-49=0 ---> given problem

step 1

Move the constant to the right side

x^{2} +10x=49

the step 1 is correct

step 2

Complete the square

x^{2} +10x+5^2=49+5^2

x^{2} +10x+5^2=74

<u><em>The step 2 is not correct</em></u>

step 3

Rewrite as perfect squares

(x+5)^{2}=74

step 4

take square root both sides

x+5=\pm\sqrt{74}

step 5

Find the values of x

x=-5\pm\sqrt{74}

x=-5+\sqrt{74}

x=-5-\sqrt{74}

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3 years ago
How you substract 7 from 52
ioda
52-7 which equals 45
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The answer is 90%. Because 10% love math you subtract 100
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2(1-4)-3(2+1) equals what
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