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My name is Ann [436]
3 years ago
13

Can a prime number be a multiple of any other number except itself. Explain why or why not

Mathematics
1 answer:
zzz [600]3 years ago
5 0
No, by definition a prime number is one where the only factors are 1 and itself. If some prime number is a multiple of another number, then that other number is a factor of the prime number. But that would make it composite (non-prime)

For example, the number 11 is prime. The only factors are 1 and itself. If we made the claim that 11 is a multiple of 2, then 2 would be a factor of 11 making 11 non-prime (as it doesn't just have 1 and itself as factors).

Note: If you have two numbers A and B, and you say that A is a factor of B, then A is the smaller value. Though there is the exception when A = B. For example, saying "8 is a factor of 16" has 8 being the smaller value.

Another note: if you say "A is a multiple of B", then B is larger than A. The exception is when A = B. Example: "100 is a multiple of 5"
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Read 2 more answers
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
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