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3 years ago

Can a prime number be a multiple of any other number except itself. Explain why or why not

1 answer:

5 0

No, by definition a prime number is one where the only factors are 1 and itself. If some prime number is a multiple of another number, then that other number is a factor of the prime number. But that would make it composite (non-prime)

For example, the number 11 is prime. The only factors are 1 and itself. If we made the claim that 11 is a multiple of 2, then 2 would be a factor of 11 making 11 non-prime (as it doesn't just have 1 and itself as factors).

Note: If you have two numbers A and B, and you say that A is a factor of B, then A is the smaller value. Though there is the exception when A = B. For example, saying "8 is a factor of 16" has 8 being the smaller value.

Another note: if you say "A is a multiple of B", then B is larger than A. The exception is when A = B. Example: "100 is a multiple of 5"

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Are the polygons similar? If they are, write a similarity statement and give the scale factor. The figures are not drawn to scal

Ugo [173]

The answer is C.
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3 years ago

QUESTION 6 of 10: Your plan for your T shirt business calls for you to be able to produce 60,000 screen printed shirts in a mont

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Factor the following: 1. 5(a+3)²- (a+3 2. p²- 6 - q · (p²- 6)²

scoundrel [369]

Answer:

1. $(a + 3)(5a-14)$

2. $(p^2-6)[1-q(p^2-6)]$

Step-by-step explanation:

1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.

Then the expression. $5(a + 3)^2- (a + 3)$ remains as:

$(a + 3)(5 (a + 3) -1)\\\\(a + 3)(5a +15 -1)\\\\(a + 3)(5a-14)$

2. The first thing to do to factor the expression is to take the expression $p^2 -6$ as its common factor with its lowest exponent.

Then the expression $p^2- 6 - q(p^2- 6)^2$ remains as:

$(p^2-6)[1-q (p^2-6)]$

8 0

3 years ago

Simplify 3^5/3^2. I do have a basic understanding but I need help on this.

ahrayia [7]

The answer is: " 27 " .
__________________________________________

3⁵ / 3² = 3⁽⁵⁻²⁾ = 3³ = 3 * 3 * 3 = 9 * 3 = 27 .
__________________________________________
-Edit -- Note the following property of exponents : "quotient rule" of exponents:
_____________________________________________
Given that "a" and "b" are positive integers; and that "x" is a real number greater than "zero";
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If a ≥ b , then:

xᵃ /xᵇ = x⁽ᵃ ⁻ ᵇ⁾ ;
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If a 
xᵃ /xᵇ = x⁽ᵇ ⁻ ᵃ⁾
____________________________________________

7 0

4 years ago

Write an equation of the circle with center (3,-2) and radius 6

Lubov Fominskaja [6]

Answer:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

Step-by-step explanation:

We want to write the equation of a circle with a center at (3, -2) and a radius of 6 units.

Recall that the equation of a circle is given by:

$\displaystyle (x-h)^2 + (y-k)^2 = r^2$

Where (h, k) is the center and r is the radius.

Since our center is at (3, -2), h = 3 and k = -2. r = 6. Substitute:

$\displaystyle (x-(3))^2 +(y-(-2))^2 = (6)^2$

Simplify:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

In conclusion, the equation of the circle will be:

$\displaystyle (x-3)^2 + (y+2)^2 = 36$

8 0

3 years ago