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3 years ago

If cos Θ = negative 4 over 7, what are the values of sin Θ and tan Θ?

1 answer:

7 0

Given cos theta is equal to - 4/ 7 then we can conclude that theta is in the second and third quadrants. In this case, the other leg is equal to square root of (7^2 - 4^2 ) equal to square root of 33. In this case, sin theta can be equal to +- square root of 33 / 7 and tan theta is equal to +-square root of 33 / 4.

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What is the solution of this equation -6+5x=6x-7

fomenos

Answer:

x = 1

Step-by-step explanation:

Our goal is to isolate x on one side. So:

-6 +5x = 6x - 7

-6 = x - 7

1 = x

Hope that helped!

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3 years ago

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olasank [31]

Answer:

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In slope-intercept form, the equation would be y = -7x + 11

You could find the slope by using the slope equation, $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ .

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3 years ago

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Viefleur [7K]

Answer:

True

Step-by-step explanation:

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3 years ago

(-2q^4)(-8q^3b^6)<br>help I need to simplify this problem

Montano1993 [528]

Multiply the constants. Multiply the variables according to the rules of exponents.
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4 0

3 years ago

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Novay_Z [31]

Answer:

Type II error

Step-by-step explanation:

According to the definition of type II error, the type II error arises when we wrongfully accept the null hypothesis. It means that when we accept our null hypothesis and null hypothesis is not correct then type II error arises. So according to situation we are accepting the null hypothesis that the food is safe but it is actually not safe. Hence the given situation represents type II error.

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3 years ago