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cluponka [151]
3 years ago
11

What is the answer for 60x-24= ? Apply the distributive property and the greatest common factor to write an equivalent expressio

n
Mathematics
2 answers:
Leni [432]3 years ago
7 0

Answer:

Is your answer 12(5x-2)

Klio2033 [76]3 years ago
3 0

You answer is 12(5x-2).

You might be interested in
In a recent poll, only 8% of the people surveyed against a new bill making it mandatory to recycle. how many of the 75 people wh
Naddik [55]
8% = 0.08
0.08 * 75 = 6

6 people surveyed.

Please make this answer the brainiest!
4 0
3 years ago
Someone know how to do this?: 6x2+18x=0
Crazy boy [7]
The answer to the question is: Yes.

Explanation:  It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.

Since I'm here already, here is the solution to this one:

6x² + 18x = 0

Divide each side of the equation by 6 :

x² + 3x = 0

Factor the left side:

x(x+ 3) = 0

This statement is true if x=0 or if x=3.

The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
4 0
3 years ago
X^2+y^2=169, 3x+2y=39 please answer using substitution and each step
Oksanka [162]

Answer:

x=13,y=0

Step-by-step explanation:

We are given a system of equations

{x}^{2}  +  {y}^{2}  = 169 -  - eqn \: 1 \\ 3x + 2y = 39 -  - eqn \: 2

For equation 1,square all terms to reduce it

√x²+√y²=169

x+y=13

Make x the subject as required by the question to use substitution method

x=13-y

Plug x=13-y into eqn 2

3(13-y)+2y=39

39-3y+2y=39

39-y=39

y=39-39=0

Plug y=0 into equation 1

x+0=13

x=0

7 0
2 years ago
Solve for a<br> -8 = a(2+5)^2 +41<br> A. -1<br> B. 1<br> C. -2<br> D. 2
mario62 [17]

Answer:A

Step-by-step explanation:

-8=a(2+5)^2 + 41

-8=a x 7^2 + 41

-8=a x 7 x 7 +41

-8=49a+41

Collect like terms

-8-41=49a

-49=49a

Divide both sides by 49

-49/49=49a/49

-1=a

a=-1

5 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
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