Methanol is an important solvent. it is also an important starting material for the synthesis of other molecules. most methanol
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Given :
A gas with a volume of 2 L at 25°C is placed into a container that is 4 L.
To Find :
The new temperature of the gas.
Solution :
Since, their is no information regarding pressure. We will assume that pressure is constant.
Now, we know when at constant pressure, volume is directly proportional to volume.
Therefore, the new temperature of the gas is 596 - 273 K = 323 K.
The maximum amount of produced during the experiment can be find out by knowing the Limiting Reagent.
Here, The maximum amount of produced during the experiment is 400 grams
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is stopped.
Now, According to the question,
Given ;
Number of moles of - 4 moles
Number of moles of NaCl - 9 moles
To Find - Maximum amount of produced during the reaction.
Solution ;
complete reaction ;
+ 3NaCl -->
+
To find the maximum amount of produced during the reaction,
we need to find the limiting reagent.
Mole ratio = 4/1 = 4
Mole ratio NaCl = 9/3 = 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of
9 moles of NaCl will produce = 1/3 x 9 = 3 moles.
Weight of = 3 x 133.34 = 400 grams
Thus, 400 grams of is the maximum amount of
produced during the experiment.
Learn more about Limiting Reagent Here ;
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