Identify the product of radioactive decay and classify the given nuclear reactions accordingly.
2 answers:
The product of radioactive decay :
- ₂He⁴
- ₋₁e⁰
- γ
- ₁e⁰
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
Information:
T = duration of decay
t1 / 2 = elemental half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
At the core, the reaction applies the law of eternity
• 1. energy
the energy before and after the reaction is the same
• 2. atomic number
the number of atomic numbers before and after the same
• 3. mass number
the number of mass numbers before and after the same
Particles that play a role in core reactions include
• alpha α particles ₂He⁴
atomic number decreases by 2, mass number decreases by 4
• beta β ₋₁e⁰ particles
atomic number remains the same , mass number decreases by -1
• gamma particles γ
Core reactions that occur usually release high energy
• positron particles ₁e⁰
atomic number remains the same , mass number decreases by +1
In general, the core reaction equation can be written:
<h3>X + a ---> Y + b + Q </h3>
X = target core
a = particle fired
Y = new core
b = the particle produced
Q = heat energy
or can be written simply
X (a, b) Y
<h3>Learn more </h3>the identity of the missing nucleus
the process of radioactive decay
nuclear fusion and nuclear fission reactions
the product of radioactive decay
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3 L will be the final volume for the gas as per Charle's law.
Answer:
Explanation:
The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.
V∝ T
Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be
So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.
So, 3 L will be the final volume for the gas as per Charle's law.