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Harrizon [31]
3 years ago
6

Identify the product of radioactive decay and classify the given nuclear reactions accordingly.

Chemistry
2 answers:
USPshnik [31]3 years ago
8 0
Radioactive decay is the means by which unstable nuclei move towards stability by emitting energy and subatomic particles. The types are:

Alpha particle decay:
Alpha particles, which are identical to helium nuclei, are released. The atomic mass of the substance decreases by 4 units and the atomic number decreases by 2.

Beta particle decay:
These particles are similar to mass as an electron, and during this decay, the atomic mass remains the same but atomic number increases by 1.

Gamma ray decay:
Gamma rays are released, which are high energy electromagnetic waves, by some radioactive nuclei to rid the excess energy they have.
Eva8 [605]3 years ago
8 0

The product of radioactive decay :

  • ₂He⁴
  • ₋₁e⁰
  • γ
  • ₁e⁰
<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles

General formulas used in decay:

\large {\boxed {Nt = No. (\frac {1} {2}) ^ {\frac {T} {t1 / 2}}}}

Information:

T = duration of decay

t1 / 2 = elemental half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

At the core, the reaction applies the law of eternity

• 1. energy

the energy before and after the reaction is the same

• 2. atomic number

the number of atomic numbers before and after the same

• 3. mass number

the number of mass numbers before and after the same

Particles that play a role in core reactions include

• alpha α particles ₂He⁴

atomic number decreases by 2, mass number decreases by 4

• beta β ₋₁e⁰ particles

atomic number remains the same , mass number decreases by -1

• gamma particles γ

Core reactions that occur usually release high energy

• positron particles ₁e⁰

atomic number remains the same , mass number decreases by +1

In general, the core reaction equation can be written:

<h3>X + a ---> Y + b + Q </h3>

 

X = target core

a = particle fired

Y = new core

b = the particle produced

Q = heat energy

or can be written simply

X (a, b) Y

<h3>Learn more </h3>

the identity of the missing nucleus

brainly.com/question/4207569

the process of radioactive decay

brainly.com/question/1770619

nuclear fusion and nuclear fission reactions

brainly.com/question/1949468

the product of radioactive decay

brainly.com/question/6029197

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Igoryamba

Answer:

The four characrteristics of warm blooded animals are÷

Explanation:

i=They can keep its body temperature the same no matter what the outside temperature .

ii=They can maintain a constant body temperature.

iii=They obtain energy from food consumption.

iv=They maintain their body temperature higher than environment.

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Some examples of combustion are:

Fossil fuel:

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Answer: 0.100 m K_2SO_4

Explanation:

Elevation in boiling point is given by:

\Delta T_b=i\times K_b\times m

\Delta T_b=T_b-T_b^0 = Elevation in boiling point

i= vant hoff factor

K_b = boiling point constant

m= molality

1. For 0.100 m K_2SO_{4}

K_2SO_4\rightarrow 2K^{+}+SO_4^{2-}  

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be 3\times 0.100=0.300

2. For 0.100 m LiNO_3

LiNO_3\rightarrow Li^{+}+NO_3^{-}  

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3.  For 0.200 m C_2H_8O_3

, i= 1 as it is a non electrolyte and does not dissociate, concentration of ions will be 1\times 0.200=0.200

4. For 0.060 m Na_3PO_4

Na_3PO_4\rightarrow 3Na^{+}+PO_4^{3-}  

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be 4\times 0.060=0.24m

Thus as concentration of solute is highest for K_2SO_4 , the elevation in boiling point is highest and thus has the highest boiling point.

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