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xz_007 [3.2K]
3 years ago
5

Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x. ax + bx - c = 0

Mathematics
2 answers:
Stolb23 [73]3 years ago
4 0
ax+bx-c=0\\
x(a+b)=c\\
x=\dfrac{c}{a+b}
JulsSmile [24]3 years ago
3 0
ax+bx-c=0 \ \ \ |+c \\
ax+bx=c \\
(a+b)x=c \ \ \ |\div (a+b), a+b \not= 0 \\
\boxed{x=\frac{c}{a+b}}
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Answer:

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Evaluate 48/6-10/3 please and thank you :)))
vodomira [7]

Answer:

14/3

Step-by-step explanation:

Simplify the following:

48/6 - 10/3

Hint: | Reduce 48/6 to lowest terms. Start by finding the GCD of 48 and 6.

The gcd of 48 and 6 is 6, so 48/6 = (6×8)/(6×1) = 6/6×8 = 8:

8 - 10/3

Hint: | Put the fractions in 8 - 10/3 over a common denominator.

Put 8 - 10/3 over the common denominator 3. 8 - 10/3 = (3×8)/3 - 10/3:

(3×8)/3 - 10/3

Hint: | Multiply 3 and 8 together.

3×8 = 24:

24/3 - 10/3

Hint: | Subtract the fractions over a common denominator to a single fraction.

24/3 - 10/3 = (24 - 10)/3:

(24 - 10)/3

Hint: | Subtract 10 from 24.

| 2 | 4

- | 1 | 0

| 1 | 4:

Answer:  14/3

5 0
3 years ago
PLEASE HELP DEADLINE IN 20 MINS​
wel

Answer:

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6 0
3 years ago
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krek1111 [17]

Answer:

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Step-by-step explanation:

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