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3 years ago

Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x. ax + bx - c = 0

Mathematics

2 answers:

Stolb23 [73]3 years ago

4 0

$ax+bx-c=0\\
x(a+b)=c\\
x=\dfrac{c}{a+b}$

JulsSmile [24]3 years ago

3 0

$ax+bx-c=0 \ \ \ |+c \\
ax+bx=c \\
(a+b)x=c \ \ \ |\div (a+b), a+b \not= 0 \\
\boxed{x=\frac{c}{a+b}}$

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Step-by-step explanation:

Lets define the following letters for each name:

A is AJ

B is Blaze

L is Laurence

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Now we will analyze the phrases one by one:

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$A = 3 * L$

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$A + B + J + L = 1092$

We replace A, B & J in the last equation, with the previous results:

$A + B + J + L = 1092$

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3 years ago