Question

Given that a, b, and c are non-zero real numbers and a + b ≠ 0, solve for x. ax + bx - c = 0

Answer 1

$ax+bx-c=0\\ x(a+b)=c\\ x=\dfrac{c}{a+b}$

Answer 2

$ax+bx-c=0 \ \ \ |+c \\ ax+bx=c \\ (a+b)x=c \ \ \ |\div (a+b), a+b \not= 0 \\ \boxed{x=\frac{c}{a+b}}$