Answer:
Force that holds atoms together in a metallic substance.
Explanation:
Hope this helps? C:
~Chiena
Answer:
7.13mL
Explanation:
P₁V₁T₁ = P₂V₂T₂
P₁ = 3atm , V₁ = 2.1 mL , T₁ = 273 + 4 =277K
P₂ = 0.95atm , V₂ = ? , T₂ = 273 + 25 =298K
V₂ = P₁V₁T₂ / P₂T₁
V₂ = (3atm)(2.1 mL )(298K) / (0.95atm)(277K)
V₂ = 7.13mL
Answer:
45.31 J
Explanation:
We are given that
Mass of baseball , m=0.145 kg
Initial velocity, u=0
Final velocity, v=25 m/s
We have to find the work done on the baseball to bring it from rest to 25 m/s
We know that
Work done = Change in kinetic energy
Work done, W=
Using the formula
Work done, W
Work done=
Work done, W=45.31 J
Hence, the work done on the baseball to bring it from rest to 25 m/s
=45.31 J
Answer:
Induced emf of the wire is 6.36 Volts.
Explanation:
It is given that,
Length of the wire, l = 75 cm = 0.75 m
Magnetic field, B = 0.53 T
Velocity, v = 16 m/s
The wire is moving straight up in the magnetic field. So, an emf is induced in the wire. It is given by :



So, the induced emf of the wire is 6.36 V. Hence, the correct option is (b) "6.36 V".
Elizabeth, weight formula is 624 divided by 9.8 which is greater than 57kg