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3 years ago

How many factors does an experimenter change?

Physics

2 answers:

borishaifa [10]3 years ago

8 0

Answer:

One.

Explanation:

In a scientific experiment, you should only change one factor, or variable, at a time. All the other factors need to stay the same, or constant. If you change more than one factor at a time, you won't be able to tell which factor is the reason for the change in results.

Liono4ka [1.6K]3 years ago

8 0

The factor that is purposely changed by the experimenter; the factor the experimenter decides to change . ... What did the experimenter change on purpose? The level of the independent variable. The changes that are made in the dependent variable. So One )

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If mechanical energy is conserved in a system the energy at any point in time can be in the form of

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3 years ago

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bulgar [2K]

Answer:

$Va-Vb=168KV$

Explanation:

From the question we are told that

Two points charge of 4\mu C and 2\mu C

Generally we find the Va and Vb individually to find there difference

Given a rectangle with two equal sides each,Assume lengths for bot sides

Length L=0.3

Breath B=0.4

Diagonal D= $\sqrt{0.3^2+0.4^2} =0.5$

at opposite sides

Mathematically Va can represented as

$Va =k(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{4*10^_-_6}{0.3} +\frac{-2*10^_-_6}{0.5} )$

$Va =9*10^9(0.00001333333-0.000004} )$

$Va =84000V$

$Va =84KV$

Mathematically Vb is represented as

$Va =k(\frac{-4*10^_-_6}{0.3} +\frac{2*10^_-_6}{0.5} )$

$Va =9*10^9(\frac{-4*10^_-_6}{0.3} +\frac{+2*10^_-_6}{0.5} )$

$Va =9*10^9(-0.00001333333+0.000004} )$

$Va =-84000V$

$Va =-84KV$

Therefore

$Va-Vb=84-(-84)\\Va-Vb=84+84\\Va-Vb=168KV$

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3 years ago

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3 years ago

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Travka [436]

Answer:

Explanation:

Given that,

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Small wheel radius

r₁ = 18cm

Bigger wheel radius.

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F₂ =?

Since the combination of those forces did not cause the wheel to rotate,

Then, Στ = 0

F₁•r₁ —F₂•r₂ =

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4 years ago

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adelina 88 [10]

Answer:

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3 years ago