Answer:
y₀ = 1020.3 m
Explanation:
This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.
y = y₀ + t - ½ g t²
when it reaches the ground its height is zero
0 = y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 14.43²
y₀ = 1020.3 m
Answer:
a = 1.34 m/s²
Explanation:
given,
mass of the attendant(M) = 75 Kg
mass of cart (m)= 27 Kg
Backward force exerted on floor (F)= 155 N
frictional force on the cart (f)= 18 N
acceleration
F_{net} = F - frictional force
F_{net} = 155 N - 18 N
F_{net} = 137 N
now,
a = 1.34 m/s²
the acceleration produced when flight attendant is equal to a = 1.34 m/s²
Answer:
Explanation:
= Mass of ball = 0.12 kg
tex]m_{2}[/tex] = Mass of bottle = 2.4 kg
= Initial velocity of ball
= Initial velocity of bottle
= Final velocity of ball =
= Final velocity of bottle
As linear momentum is conserved
The bottle's speed is
The solution to your problem is as follows:
a=dv/dt=2*0.82*twhat time velocity is 13.7 solve 13.7=0.82*t^2 t=sqrt(13.7/0.82) =4.51 sUse the time in the acceleration expression a= 2*0.82*4.51=7.39m/s^2
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