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Harlamova29_29 [7]
3 years ago
7

Liam has 9/10 gallon of paint for painting the bird houses he sells at the craft fair each birdhouse requires 1/20 gallon of pai

nt how many birdhouses can liam paint
Mathematics
1 answer:
Rina8888 [55]3 years ago
6 0
So to get the fractions easier to understand you need to put them on the same level you are on. So change the 9/10 gallons to 18/20 ( this makes them easier to deal with the 1/20)
so put 1/20 into 18/20. Liam can paint 18 bird houses.
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The Mean Absolute Deviation is - 0 +0+0+1+3+8 = 24/ 6 which would = 4 that's the answer to your question .

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Who discovered the world's smallest Glacier
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A genetic experiment involving peas yielded one sample of offspring consisting of 437437 green peas and 129129 yellow peas. Use
navik [9.2K]

Answer:

The null hypothesis: \mathbf{H_o: p=0.27}

The alternative hypothesis: \mathbf{H_1: p \neq 0.27}

Test statistics : z = −2.30

P-value:  = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

Step-by-step explanation:

From the given information:

Let's state the null and the alternative hypothesis;

Since The claim is that 27%  of the offspring peas will be yellow.

The null hypothesis state that the proportion of offspring peas will be yellow is equal to 0.27.

i.e

\mathbf{H_o: p=0.27}

The alternative hypothesis  state that the proportion of offspring peas will be yellow is not equal to 0.27

\mathbf{H_1: p \neq 0.27}

<u>The test statistics:</u>

we are given 437 green peas and 129 yellow apples;

Hence;

\hat p = \dfrac{x}{n}

where ;

\hat p = sample proportion

x = number of success

n = total number of the sample size

\hat p = \dfrac{129}{437+129}

\hat p = \dfrac{129}{566}

\mathbf{\hat p = 0.2279}

Now; the test statistics can be computed as :

z = \dfrac { \hat p -p }{\sqrt {\dfrac{p(1-p)}{n}  } }

z = \dfrac {0.2279 -0.27 }{\sqrt {\dfrac{0.27(1-0.27)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.27(0.73)}{566}  } }

z = \dfrac {-0.043 }{\sqrt {\dfrac{0.1971}{566}  } }

z = \dfrac {-0.043 }{\sqrt {3.48233216*10^{-4} } }

z = \dfrac {-0.043 }{0.01866} }

z = −2.30

C. P-value

P-value = P(Z < z)

P-value = P(Z< -2.30)

By using the ​ P-value method and the normal distribution as an approximation to the binomial distribution.

from the table of standard normal distribution

move left until the first column is reached. Note the value as –2.0

move upward until the top row is reached. Note the value as 0.30

find the probability value as 0.010724 by the intersection of the row and column values gives the area to the left of

z = -2.30

P- value = 2P(z ≤ -2.30)

P-value = 2 × 0.01072

P - value = 0.02144

Decision Rule: Since the p-value is lesser than the level of significance; then we reject the null hypothesis.

Conclusion: We accept the alternative hypothesis and  conclude that under the same​ circumstances the proportion of offspring peas will be yellow is not equal to 0.27

8 0
3 years ago
A GMC dealer believes that demand for 2005 Envoys will be normally distributed with a mean of 200 and standard deviation of 30.
irina1246 [14]

Answer:

The correct answer to the following question will be "280 units".

Step-by-step explanation:

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Now,

⇒  Mean + 3\times sigma

On putting the values, we get

⇒  200+3\times 30

⇒  200+90

⇒  290 \ units

290 units would then accomplish a level of service of 99.9%.

Half unpurchased units can indeed be purchased at $30000 i.e. no failure. If he requests 300, there will be losses on 5 products that are unsold.

Hence, ordering 280 units seems to be preferable

3 0
3 years ago
12 + n/5 = 16 what is n
Orlov [11]

Answer:

5×16=80

80-12=68

n=68

5 0
3 years ago
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