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lawyer [7]
3 years ago
14

A contractor had $3,285 to spend for doors and hammers. Doors cost $75 each. He bought the greatest number of doors that he coul

d buy. He will use the money he has remaining to buy hammers that cost $15 each. What is the greatest number of hammers the contractor can buy with the money he has remaining?

Mathematics
1 answer:
swat323 years ago
6 0

Answer:

4 hammers

Step-by-step explanation:

Please refer to the attached image for explanations

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(6 x 9 = f) f x 16 = b <br><br> what dose b equal
Tcecarenko [31]

Step-by-step explanation:

f=6×9

aubstituting f=6×9

6×9×16=b

864=b

4 0
3 years ago
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What
NNADVOKAT [17]
The answer is -130. hope this helps.
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3 years ago
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The slope of (17,2) and (18,-17)
Ahat [919]

<u>m= -19/1</u>

We need to use the slope equation

\frac{y_{2}-y_{1}  }{x_{2}-x_{1} }

We are working with the points,  

 (17,    2)         and      (18,     -17)

  x1    y1                       x2       y2

\frac{-17-2}{18-17}

<u>m= -19/1</u>

4 0
3 years ago
What is 20 x 14 = ? :))))
m_a_m_a [10]

Answer:

The answer is 280

5 0
3 years ago
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Somebody please help so I can pass, please
ASHA 777 [7]
First, we are going to find the vertex of our quadratic. Remember that to find the vertex (h,k) of a quadratic equation of the form y=a x^{2} +bx+c, we use the vertex formula h= \frac{-b}{2a}, and then, we evaluate our equation at h to find k.

We now from our quadratic that a=2 and b=-32, so lets use our formula:
h= \frac{-b}{2a}
h= \frac{-(-32)}{2(2)}
h= \frac{32}{4}
h=8
Now we can evaluate our quadratic at 8 to find k:
k=2(8)^2-32(8)+56
k=2(64)-256+56
k=128-200
k=-72
So the vertex of our function is (8,-72)

Next, we are going to use the vertex to rewrite our quadratic equation:
y=a(x-h)^2+k
y=2(x-8)^2+(-72)
y=2(x-8)^2-72
The x-coordinate of the minimum will be the x-coordinate of the vertex; in other words: 8.

We can conclude that:
The rewritten equation is y=2(x-8)^2-72
The x-coordinate of the minimum is 8

8 0
4 years ago
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