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sergiy2304 [10]
3 years ago
8

Find the Area of the figure below, composed of a rectangle and one semicircle, with

Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Answer:

56

Step-by-step explanation:

Simple just move the semicircle into the empty spot and there you go.

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What ratios can be equivalent to 1 and 8
mylen [45]

Answer:

2:16 , 8:64 , 5:40

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please can someone help????
Viefleur [7K]

Proof:

Consider \triangle WXZ, \triangle YZX:

\overline W\overline X = \overline Y\overline Z (given)

\angle WXZ = \angle YZX (alternate angles are equal, \overline W\overline X\parallel \overline Y\overline Z)

\overline Z \overline X is a common side

∴ \triangle WXZ \cong \triangle YZX (SAS)

Hope this helps :)

3 0
3 years ago
Find the extreme values of the function f(x, y) = 4x2 + 6y2 on the circle x2 + y2 = 1.
julia-pushkina [17]

Answer with Step-by-step explanation:

We are given that

f(x,y)=4x^2+6y^2

Let g(x,y)=x^2+y^2=1

We have to find the extreme values  of the given function

\nabla f(x,y)

\nabla g(x,y)=

Using Lagrange multipliers

\nabla f(x,y)=\lambda \nabla g(x,y)

f_x=\lambda g_x

8x=\lambda 2x

Possible value x=0 or \lambda=4

If x=0 then substitute the value in g(x,y)

Then, we get y=\pm 1

f_y=\lambda g_y

12y=\lambda 2y

If \lambda=4 and substitute in the equation

Then , we  get possible value of y=0

When y=0 substitute in g(x,y) then we get

x=\pm 1

Hence, function has possible  extreme values at points (0,1),(0,-1), (1,0) and (-1,0).

f(0,1)=6

f(0,-1)=6

f(1,0)=4

f(-1,0)=4

Therefore, the maximum value of f  on the circlex^2+y^2=1  is f(0,\pm1)=6 and minimum value of f(\pm1,0)=4

7 0
3 years ago
I need help plsssssss​
Svetllana [295]

4)Area :32cm

5)18cm

6) 49cm

4 0
3 years ago
The regular tax to be paid with any purchase is 8%. How much tax did Anthony pay if he bought school supplies worth ₱5 000?​
Dvinal [7]

Answer:

400

Step-by-step explanation:

8% of 5000 is 400. Math:

5000 x 0.08 = 400

4 0
3 years ago
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