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guapka [62]
3 years ago
7

Which equations are in standard form? Check all that apply y = 2x + 5 2x + 3y = –6 –4x + 3y = 12 y = x – 9 x + 3 = 6 x – y = 5 5

x + 3y =
Mathematics
2 answers:
Lostsunrise [7]3 years ago
8 0

Answer:

The correct answers are:

2x + 3y = –6

and

x – y = 5


Gnesinka [82]3 years ago
6 0
The right chose is -9x+3= the others are not hope this helped 

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Look at the attachment
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3 years ago
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8.98*5.67 Put in decimal form
sweet-ann [11.9K]

Answer:

50.9166

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8 0
3 years ago
A racing car consumes a mean of 100 gallons of gas per race with a variance of 64. If 44 racing cars are randomly selected, what
lesantik [10]

Answer:

83.89% probability that the sample mean would be greater than 98.8 gallons

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The standard deviation is the square root of the variance. So

\mu = 100, \sigma = \sqrt{64} = 8, n = 44, s = \frac{8}{\sqrt{44}} = 1.21

If 44 racing cars are randomly selected, what is the probability that the sample mean would be greater than 98.8 gallons

This probability is 1 subtracted by the pvalue of Z when X = 98.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{98.8 - 100}{1.21}

Z = -0.99

Z = -0.99 has a pvalue of 0.1611

1 - 0.1611 = 0.8389

83.89% probability that the sample mean would be greater than 98.8 gallons

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3 years ago
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2b + 34greater then or equal to 54

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Arnie is an american teaching english in Japan,and the currently has 55,000 yen in his bank account.If the excham=nge rate chang
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