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dusya [7]
3 years ago
9

Which expression is equivalent to -3/4 (32+24e-4f)

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

-24 -18e +3f

Step-by-step explanation:

-3/4 (32+24e-4f)

Distribute the -3/4

-3/4 * 32 + -3/4 *24e + -3/4 *-4f

-24 -18e +3f

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marissa [1.9K]

Answer:

1: False.

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Step-by-step explanation:

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8 0
2 years ago
Three fourths a number plus 8 is 20 less than the number
VARVARA [1.3K]

Answer:

Equation:  \frac{3}{4}n+8=n-20

Solve for n:  n = 112

Step-by-step explanation:

To first set up the equation, you need to look at the verbal description and translate into numbers and operations:

'three fourths a number' =  \frac{3}{4} n

'plus 8' = + 8

'is' =

'20 less' = - 20

'the number' = n

Put the expressions together:

'three fourths a number plus 8':  \frac{3}{4}n+8

'20 less than the number': n - 20

Set them equal to each other and solve: \frac{3}{4}n+8=n-20

Add 20 to both sides: \frac{3}{4}n+8+20=n-20+20

Subtract \frac{3}{4}n from both sides: \frac{3}{4}n-\frac{3}{4}n+28=n-\frac{3}{4}n

Multiply both sides by \frac{4}{1}: \frac{4}{1}28=\frac{1}{4}n\frac{4}{1}

Solve for n:  n = 112

7 0
3 years ago
20 is what percent of 25 ?
Musya8 [376]

Answer: 80%

Step-by-step explanation:

5 0
3 years ago
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If 5 is subtracted from the square of a number ,the result is 4 , find the number.
Levart [38]

Answer:

9 I think

Step-by-step explanation:

I added 5 plus 4 to get 9 but I'm really not sure but I hope i helped!

7 0
3 years ago
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
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