All categories

3 years ago

HELPPPPPP PLEASEEEEEEEEEE

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

6 0

In synthetic division, you start by bringing down the first 1 in the box. Multiply that by the 1 outside the box and get a 1. Put that new 1 under the 2 inside the box and add to get 3. Multiply the outside the box by that 3 to get 3 and put that new 3 under the -3 in the box and add to get 0. Multiply that 0 by the 1 outside the box to get 0. Put that 0 under the 2 and add to get the remainder of 2. Your answer is 2, C.

You might be interested in

Kate prepared 9 kilograms of dough after working 3 hours. How many hours did Kate work if she prepared 12 kilograms of dough? As

beks73 [17]

Answer:

4 hours

Step-by-step explanation:

cross multiply

3 0

3 years ago

Malorie can work 10 math problems in 3 minutes. At this rate, how many problems can she work in one hour?

lisov135 [29]

D
If you multiply 3 by 10 and add a zero onto the ten in the question that is 100 in half an hour, all you need to do then is multiply that answer by two to get your answer.

4 0

3 years ago

Find -3(6m-8)+(-4+2m).

mamaluj [8]

Answer: − 16 m + 20

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Marysya12 [62]

The function has a maximum at (1, 3).

_____
You know it is not a minimum because the coefficient of the squared term is negative.

You know the vertex is (1, 3) because you match the pattern to
.. y = a(x -h)^2 +k
which has its vertex at (h, k).

3 0

3 years ago

Describe and correct the error(s) made in each of the problems below.

ladessa [460]

Answer:

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

$1-x / (5-x)(-x)=x-1 / x(x-5)$

Let's arrange into format:

$\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}$

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

$\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}$

Now for the second expression

$5/s+2/5=2/s$

Let's arrange into format

$\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}$

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

$\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}$

6 0

3 years ago