Answer:
9:29 PM
Step-by-step explanation:
Let us add the number of minutes the first act, interval and second act lasted:
46 + 20 + 53 = 119 minutes
Converting this to hours and minutes:
60 minutes = 1 hour
119 minutes = 1 hour 59 minutes
Therefore, the time that the second act ends is:
H M
7 : 30 PM
+ <u> 1 : 59</u>
<u> 9 : 29 </u>
<u />
The second act will end by 9:29 PM
Answer:(0)-12,-15
Step-by-step explanation:
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
Answer:
thats the kind of work u have in 7th grade thats sad
Step-by-step explanation:
