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Kay [80]
3 years ago
8

Three consecutive integers have a sum of -21. Which equation can be used to find the value of the three numbers?

Mathematics
1 answer:
umka21 [38]3 years ago
7 0

Answer: x + (x + 1) + (x + 2) = -21

Step-by-step explanation:

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What are the values?
zavuch27 [327]

The average of a set of numbers

Step-by-step explanation:

An Example: 4×3 gives you the value of 12.

6 0
3 years ago
Read 2 more answers
If the cost 12 oranges is $6 and someone wanted to know the price of 1 orange. What vocabulary word represents the cost of that
Soloha48 [4]

Answer:

Ratio

Step-by-step explanation:

12 oranges

divided by 6 is 2$

2$ for 1 orange

2:1

7 0
3 years ago
The sum of two numbers is 16. their difference is 1. what is the product of the two numbers
Fofino [41]

Answer:

The product of the numbers is 63.75

Step-by-step explanation:

Let the numbers be x and y

x + y = 16

x -y = 1

Adding both together

2x = 17

x = 17/2

x = 8.5

Recall

x -y = 1

8.5 - y = 1

y = 8.5 - 1 = 7.5

Their product is xy

so we have 7.5 * 8.5 = 63.75

3 0
2 years ago
If A, B, and C are mutually exclusive events with P(A) = 0.2, P(B) = 0.3, and P(C) = 0.4, determine the following probabilities:
fiasKO [112]

a. The events are mutually exclusive, so

P(A\cup B\cup C)=P(A)+P(B)+P(C)=\boxed{0.9}

b. For the same reason,

P(A\cap B\cap C)=\boxed0

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

P(A\cap B\cap C)=P(A)+P(B)+P(C)-P(A\cup B\cup C)

and the right side reduces to 0.

c. Same as (b),

P(A\cap B)=\boxed0

d. Same as (b),

P((A\cup B)\cap C)=\boxed0

We can also use the distributivity rule for unions and intersections to write

P((A\cup B)\cap C)=P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)=0

e. If the A' is the complement of A, then by DeMorgan's law,

P(A'\cap B'\cap C')=P(A\cup B\cup C)'=1-P(A\cup B\cup C)=\boxed{0.1}

4 0
3 years ago
Find two different planes whose intersection is theline:x = 6 + 3ty = -8 - 3tz = -1 - tWrite equations for each plane in the for
alina1380 [7]

Answer:

x+y=-2 and 3z-y=5 are two such planes.

Step-by-step explanation:

To find the two planes whose intersection is the line

x=6+3t\\ y=-8-3t\\ z=-1-t

You can say that <em>t</em> is equal to this expression

t=\frac{x-6}{3} =\frac{y+8}{-3}=-z-1

Next,

\frac{x-6}{3} =\frac{y+8}{-3}\\ \frac{y+8}{-3}=-z-1

Then,

x+y=-2 and 3z-y=5 are two such planes.

You can see in the image attached that the intersection of this planes is the line

x=6+3t\\ y=-8-3t\\ z=-1-t

7 0
3 years ago
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