3 years ago

Three consecutive integers have a sum of -21. Which equation can be used to find the value of the three numbers?

1 answer:

7 0

Answer: x + (x + 1) + (x + 2) = -21

Step-by-step explanation:

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lapo4ka [179]

What is the question? I don't understand please explain?

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3 years ago

Kipish [7]

Answer:

f(g(x)) = x^4 + 12x^3 + 14x^2 -132x + 123

Step-by-step explanation:

Here, we simply will place g(x) into f(x)

So every x in f(x) is replaced by g(x)

Thus, we have;

(x^2 + 6x + 11)^2 + 2

= (x^2+6x-11)(x^2 + 6x -11) + 2

= x^4 + 6x^3 -11x^2 + 6x^3 + 36x^2 - 66x -11x^2 -66x + 121 + 2

= x^4 + 12x^3 + 14x^2 -132x + 123

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3 years ago

Arturiano [62]

5,595,756,198,388

Step-by-step explanation:

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3 years ago

kramer

Answer:

x = -2

Step-by-step explanation:

$-13x - 8 = 5 - 8x - 3 \\\\-13x + 8x = 5 - 3 + 8 \\\\-5x = 10 \\\\x = \frac{-10}{5} = -2$

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3 years ago

Feliz [49]

Answer:

The factor pairs of the number 48 are: 1 x 48, 2 x 24, 3 x 16, 4 x 12, and 6 x 8

Step-by-step explanation:

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3 years ago