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3 years ago

Could you please explain find an equation for i, -i, -4, 1 = x as its solution

Mathematics

1 answer:

Virty [35]3 years ago

5 0

We can do this easily using 0s.

(x - i) (x + i) (x + 4) (x - 1) = 0

If you plug in any of the numbers, you'll get 0, making the equation true.

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sammy [17]

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3 years ago

SHORT & EASY !!!!!!!!!!!

Tresset [83]

Answer:

Exact Form:

x = 9/2

Decimal Form:

x = 4.5

Mixed Number Form:

x = 4 1/2

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3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs.

Elza [17]

Answer:

Part 1) -7 → $\dfrac{y^2-y+6}{-2(y+7)}$

Part 2) 3/2 → $\dfrac{y^2-2y+1}{2y-3}$

Part 3) 1 → $\dfrac{5y^2-6y+1}{-5(y-1)}$

Part 4) -1/4 → $\dfrac{y(y+5)}{4y+1}$

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

we know that

To find out the non permissible replacements for y, equate the denominator of each expression equal to 0.

step 1

we have

$\dfrac{y^2-2y+1}{2y-3}$

Equate (2y-3) equal to 0.

$2y-3=0$

solve for y

Adds 3 both sides.

$2y=3$

Divide both sides by 2.

$y=\dfrac{3}{2}$

therefore

3/2 is the non permissible replacement for y.

step 2

we have

$\dfrac{y(y+5)}{4y+1}$

Equate (4y+1) equal to 0.

$4y+1=0$

Subtract 1 both sides

$4y=-1$

Divide by 4 both sides

$y=-\dfrac{1}{4}$

therefore

-1/4 is the non permissible replacement for y.

step 3

we have

$\dfrac{5y^2-6y+1}{-5(y-1)}$

Equate -5(y-1) equal to 0.

$-5(y-1)=0$

Divide by -5 both sides

$y-1=0$

Adds 1 both sides

$y=1$

therefore

1 is the non permissible replacement for y.

step 4

we have

$\dfrac{y^2-y+6}{-2(y+7)}$

Equate -2(y+7) equal to 0.

$-2(y+7)=0$

Divide by -2 both sides

$y+7=0$

Subtract 7 both sides

$y=-7$

therefore

-7 is the non permissible replacement for y

7 0

3 years ago

13/312500 in scientific notation

STatiana [176]

Answer is 4.16*10^-5

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4 years ago

How do i describe the function in red

kkurt [141]

Answer:

Step-by-step explanation:

The transformation from the parent function (red line) to the blue line is a translation 2 units to the left and 3 units down, and a reflection over the x-axis.

The blue line does not seem to be stretched or compressed.

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3 years ago