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maria [59]
3 years ago
7

Find the mass of the wire formed by the intersection of the sphere x 2 + y 2 + z 2 = 1 and the plane x + z = 0 if the density of

the wire is 4x 2 grams per unit length.
Mathematics
1 answer:
Marat540 [252]3 years ago
6 0
<span>Answer: x²+(â’xâ’z)²+z² = 1 → 2x²+2zx+(2z²â’1) = 0 Solve as a quadratic : x = { â’2z ± âš(4z²â’8(2z²â’1) } / 4 = { â’z ± âš(2â’3z²) } / 2 A more manageable form can be derived by setting z = âš(2/3).sint to remove âš This gives x = â’âš(1/6).sint + âš(1/2).cost (can omit ± sign since â’ is covered by Ď€â’t) Using x+y+z = 0 gives y = â’xâ’z = â’âš(1/6)sint â’ âš(1/2).cost So a parameterisation in terms of t â [0,2Ď€] is x = â’âš(1/6).sint + âš(1/2).cost, y = â’âš(1/6).sint â’ âš(1/2).cost, z = âš(2/3).sint (ds/dt)² = (â’âš(1/6).costâ’âš(1/2).sint)² + (â’âš(1/6).cost+âš(1/2).sint)² + (âš(2/3).cost)² = 1 â´ â« Ďds = â« ( â’âš(1/6).sint + âš(1/2).cost )²dt, [t=0,2Ď€] = 2Ď€/3</span>
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2 points
sattari [20]

Answer:

well the answer is 7 rides

Step-by-step explanation:

25 - 4

=21

21÷3

=7

(p.s working might not be in the right format but its right)

6 0
2 years ago
After a storm, 135 trees out of 180 were left standing. What is the percentage loss of the number of trees?
beks73 [17]

Answer:

Percentage loss of the number of trees is 25\%.

Step-by-step explanation:

Given: After a storm, 135 trees out of 180 were left standing.

To find: What is the percentage loss of the number of trees?

Solution:

We have,

Total number of trees =180

Number of trees left standing =135

Therefore, loss of trees=180-135=45

We now that \text {Loss\%}=\frac{\text{Number of trees left}}{\text{Total number of trees}}\times 100 \%

\implies \text {Loss\%}=\frac{45}{180}\times 100 \%

\implies \text {Loss\%}=\frac{450}{18} \%

\implies \text {Loss\%}=25 \%

Hence, the percentage loss of the number of trees is 25\%.

6 0
3 years ago
I NEEDDD HELPPP ITSSSSSS URGENTTTTT!!!
Georgia [21]
Answer:

100 degrees

Step-by-step explanation:

measure of FHD = 65 + 35

measure of FHD = 100
6 0
3 years ago
Read 2 more answers
Write in expanded form 72.864
Sergeeva-Olga [200]

Answer:

70 + 5 + 8/10 + 6/100 + 4/1000

Or

7*10 + 5*1 + 8*1/10 + 6*1/100 + 4*1/1000

5 0
2 years ago
Please help, Brainliest, thanks and five star
igomit [66]

Answer:

I think the answer is the fourth one

Step-by-step explanation:

6 0
2 years ago
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