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devlian [24]
3 years ago
11

Verify sin4 x- sin2x = cos4x – cos2x is an identity

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

Step-by-step explanation:

sin⁴ x − sin² x

Factor:

(sin² x) (sin² x − 1)

Pythagorean identity:

(1 − cos² x) (-cos² x)

Distribute:

-cos² x + cos⁴ x

cos⁴ x − cos² x

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a system of equations is shown below: x y = 3 2x − y = 6 the x−coordinate of the solution to this system of equations is _____.
pychu [463]
If you would like to solve the system of equations x + y = 3 and 2x - y = 6, you can do this using the following steps:

<span>x + y = 3 ... y = 3 - x
2x - y = 6
</span>_________
<span>2x - y = 6
</span>2x - (3 - x) = 6
2x - 3 + x = 6
3x = 6 + 3
3x = 9     /3
x = 9/3
x = 3

<span>y = 3 - x = 3 - 3 = 0
</span>
The correct result would be x = 3.
6 0
3 years ago
Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0
horsena [70]

Answer:

Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

Step-by-step explanation:

We need to solve the equation x^2-8x+41=0 using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i

So, Solving the equation x^2-8x+41=0 using quadratic formula we get x=4+5i \ or \ x=4-5i

5 0
3 years ago
If f(x)=x-6 and g(x)=x1/2(x+3), find g(x) times f(x)
Elden [556K]
To solve this problem you must apply the proccedure shown below:
 1. You have the following functions given in the problem above:
 f(x)=x-6 &#10; and g(x)=x1/2(x+3)=x(x+3)/2<span>
 2. You have that g(x) times f(x) can be written as g(x)*f(x). Therefore, you must multiply f(x) * g(x), as following:
 </span>g(x)*f(x)=(x-6)*x(x+3)/2<span>
 3. Applying the distributive property, you have:
</span> g(x)*f(x)=( x^{3} + 3x^2 - 6x^{2} -18x)/2
 g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
 The answer is:  g(x)*f(x)=(x^{3} - 3x^{2} -18x)/2
5 0
3 years ago
Yooo this trippy help
lilavasa [31]

Answer:

-2150000

Step-by-step explanation:

I hope this right cause my head hurt doing that

5 0
3 years ago
Which of the following statements are always true when a transversal crosses parallel lines? 1.Several congruent angles are form
slavikrds [6]
Statements that are always true are:1. Several congruent angles are formed.4. Supplementary angles are formed.Other statements are not always true when a transversal crosses parallel lines.

6 0
3 years ago
Read 2 more answers
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