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devlian [24]
3 years ago
11

Verify sin4 x- sin2x = cos4x – cos2x is an identity

Mathematics
1 answer:
Andrej [43]3 years ago
6 0

Step-by-step explanation:

sin⁴ x − sin² x

Factor:

(sin² x) (sin² x − 1)

Pythagorean identity:

(1 − cos² x) (-cos² x)

Distribute:

-cos² x + cos⁴ x

cos⁴ x − cos² x

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The expression will be 589/15 
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The value of πPhone stock has increased 9% each year for the past several years. In 2020, the stock was worth $75. What will the
Iteru [2.4K]

Answer:

2027 = $122.25

2016 = $48

Step-by-step explanation:

Find 1% of 75

75 / 100 = 0.75

multiply by 9

0.75 * 9 = 6.75

So that's $6.75 each year

Now, lets find our answers for 7 years.

6.75 * 7 = $47.25

75 + 47.25 = $122.25

<u>The stock will be $122.25 in 2027</u>

Now for 2016.

$6.75 * 4 = $27

$75 - $27 = $48

<u>The stock was $48 in 2016</u>

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3 years ago
Plz help me it’s about apex and I just need the answer bc I don’t understand
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The variable can be g for games being bowled and the expression is 25g
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3 years ago
Anyone a single pringle and i need help 500 divided by 23 times 3
baherus [9]

Answer:

65.21739130434783

Step-by-step explanation:

5 0
2 years ago
At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
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