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worty [1.4K]
3 years ago
5

The diagonals of rectangle nopq intersect at point r. if qr=3x-4 and np=5x+20, solve for x.

Mathematics
2 answers:
FrozenT [24]3 years ago
7 0
2(3x - 4) = 5x + 20
6x - 8 = 5x + 20
subtract 5x from both sides
x - 8 = 20
add 8 to both sides
x = 28


Yuki888 [10]3 years ago
7 0

Answer:

The value of "x" is 28.

Step-by-step explanation:

As can see in the attach the length of both diagonals is the same. From the problem, you have the length of segment qr = 3x -4, which represents half of the diagonal. Then, length of segment np = 5x + 20, is the completa diagonal. So, you have to multiply the equation for qr by 2 and then equal it to equation of segment np.

2·(3x - 4) = 5x + 20 ⇒ 6x - 8 = 5x + 20 ⇒ 6x - 5x = 20 + 8 ⇒ x = 28.

Summarizing the value of "x" is 28.

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Calculate the perimeter and area of the triangle formed by the coordinates K (-4,-1) ,L(-2, 2), and M (3,-1).
Y_Kistochka [10]

Perimeter = 16.4 units

Using the heron's formula, Area ≈ 10.4 units².

<h3>What is the Heron's Formula?</h3>

The heron's formula is used to find the area of a triangle with known side lengths of all its three sides, a, b, and c. The heron's formula is given as: Area = √[s(s - a)(s - b)(s - c)], where s = half the perimeter of the triangle

s = (a + b + c)/2.

Given the following:

K (-4,-1) ,

L(-2, 2),

M (3,-1)

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}, to find KL, LM, and KM.

KL = √[(−2−(−4))² + (2−(−1))²]

KL = √13 ≈ 3.6 units

LM = √[(−2−3)² + (2−(−1))²]

LM = √34 = 5.8 units

KM = √[(−4−3)² + (−1−(−1))²]

KM = √49 = 7 units

Perimeter = 3.6 + 5.8 + 7 = 16.4 units

Semi-perimeter (s) = 1/2(16.4) = 8.2 units

KL = a ≈ 3.6 units

LM = b = 5.8 units

KM = c = 7 units

s = 8.2

Plug in the values into √[s(s - a)(s - b)(s - c)]

Area = √[8.2(8.2 - 3.6)(8.2 - 5.8)(8.2 - 7)]

Area = √[8.2(4.6)(2.4)(1.2)]

Area = √108.6336

Area ≈ 10.4 units²

Learn more about heron's formula on:

brainly.com/question/10713495

#SPJ1

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