The diagonals of rectangle nopq intersect at point r. if qr=3x-4 and np=5x+20, solve for x.
2 answers:
Answer:
The value of "x" is 28.
Step-by-step explanation:
As can see in the attach the length of both diagonals is the same. From the problem, you have the length of segment qr = 3x -4, which represents half of the diagonal. Then, length of segment np = 5x + 20, is the completa diagonal. So, you have to multiply the equation for qr by 2 and then equal it to equation of segment np.
2·(3x - 4) = 5x + 20 ⇒ 6x - 8 = 5x + 20 ⇒ 6x - 5x = 20 + 8 ⇒ x = 28.
Summarizing the value of "x" is 28.
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Answer:
A: -41/9
Step-by-step explanation:
Substitute the point (4, -5) and slope -1/9 into the equation y = mx + b.
-5 = -1/9(4) + b
-5 = -4/9 + b
Solve for b:
b = -41/9
Our equation: y = -1/9(x) - 41/9
