On your paper, you wrote down a^2+b^2 = c^2 which is the pythagorean theorem
You are on the right track. You'll use this equation. In this case
a = 36
b = 18
c = 43
The value of a and b can be swapped. The value of c is always the longest side.
Let's see if a^2+b^2 = c^2 is true or not
a^2 + b^2 = c^2
36^2 + 18^2 = 43^2
1296 + 324 = 1849
1620 = 1849
The last equation is false so the first equation is false when a = 36, b = 18 and c = 43
We do NOT have a right triangle so we do NOT have a rectangle
Answer: No, the table is not "square" (ie, have right angles at the corners)
Answer:
x=4.5
Step-by-step explanation:
so when y=20 and x=2, y is 10 times x so, <u>45/10=4.5</u>
Answer:
D
Step-by-step explanation:
X+y=0
x = -y
-y-y+2=0
-2y=-2
y=1
x+1=0
x=-1
(-1,1)
First convert the mixed numbers into fractions:
2 1/6 = 13/6
4 2/3 = 14/3
Now add the fractions:
13/6 + 14/3 = (13 + 14*2)/6 = (13+28)/6 = 41/6
Now convert it back to mixed number
41/6 = 6 5/6
thus 2 1/6 + 4 2/3 = 6 5/6
Hope it helps!
