Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
Answer:
45
Step-by-step explanation:
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Answer:
10/48 - 2/24 - 1/12
Step-by-step explanation:
answer is 1/12
Answer:
78 79 80
Step-by-step explanation:
Let the smallest number = x
Let the next number = x + 1
Let the largest number = x + 2
x + x + 1 + x + 2 = 237 Add together to get the equation
3x + 3 = 237 Subtract 3 from both sides.
3x + 3 - 3 = 237 - 3 Combine the right
3x = 234 Divide by 3
x = 234/3
x = 78
The smallest number is 78
The next number 79
The highest number is 80
