Chemical energy turns into heat and light energy.
There’s energy stored(potential) in the log, so when it burns, that energy is released as light and heat
The balanced equation for the above reaction is as follows;
<span>Fe</span>₂<span>O</span>₃<span> + 3 CO --> 2 Fe + 3 CO</span>₂
<span>stoichiometry of CO to Fe is 3:2
molar volume states that 1 mol of any gas occupies a volume of 22.4 L
If 22.4 L contains 1 mol of CO
Then 3.65 L contains - 1/22.4 x 3.65 = 0.16 mol
3 mol of CO forms 2 mol of Fe
Then 0.16 mol of CO forms - 2/3 x 0.16 = 0.1067 mol of Fe
Therefore mass of Fe produced - 0.1067 mol x 55.8 g/mol = 5.95 g</span>
Answer:
0.067 M
Explanation:
Given data:
Volume of solution = 1.00 L
Mass of BaCl₂ = 14 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will calculate the number of moles first.
Number of moles = mass/ molar mass
Number of moles = 14 g/ 208.23 g/mol
Number of moles = 0.067 mol
Now we will calculate the molarity.
Molarity = 0.067 mol / 1.00 L
Molarity = 0.067 M ( mol/L=M)
When the temperature increases,the particles will conduct successful collisions and the rate of reaction will also increase
The product will not be affected by the addition of twice as much Na₂CO₃.
<h3>What is Limiting reagent in stoichiometry ?</h3>
- The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
- The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
- Calculate the moles of each reactant present and contrast it with the mole ratio of the reactants in the balanced equation to determine which reactant is the limiting one.
Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.
To know more about the Limiting reactant, refer to:
brainly.com/question/14222359
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