2 nf3 + 225 kj -> n2 + 3f2 is it exothermic or endothermic

1 answer:

6 0

Due to energy being a reactant instead of a product, the process is endothermic. The system must absorb a quantity of energy before it can react, so it must be an endothermic system.

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Methane and chlorine react to form four products: CH3Cl, CH2Cl2, CHCl3, and CCl4. At a particular temperature and pressure, 38.4

Anastasy [175]

Answer:

How many grams of CCL4 were formed? 116.9 g

How many grams of Cl2 reacted with the CH4? 243.8 g

Explanation:

First we need to know the molar mass for every element or compound in the reaction:

$M_{CH_{4}}=16 g/mol\\M_{CH_{3}Cl}=50.49g/mol\\M_{CH_{2}Cl_{2}}=84.93g/mol\\M_{CHCl_{3}}=119.38g/mol\\M_{CCl_{4}}=153.82g/mol$

Now we proceed to calculate the amount of moles produced, per product:

$n_{CH_{4}}=2.4\\n_{CH_{3}Cl}=0.18\\n_{CH_{2}Cl_{2}}=0.55\\n_{CHCl_{3}}=0.91\\n_{CCl_{4}}=n_{CH_{4}}-(n_{CH_{3}Cl}+n_{CH_{2}Cl_{2}}+n_{CHCl_{3}})\\n_{CCl_{4}}=0.76mol\\m_{CCl_{4}}=n_{CCl_{4}}*M_{CCl_{4}}\\m_{CCl_{4}}=116.9g$

To calculate the mass of chlorine we just need to make a mass balance:

$m_{CH_{4}}+m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}\\m_{Cl_{2}}=m_{CH_{3}Cl}+m_{CH_{2}Cl_{2}}+m_{CHCl_{3}}+m_{CCl_{4}}-m_{CH_{4}}\\m_{Cl_{2}}=243.8g$

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2 years ago

For the reaction 2SO2+O2 ---> 2SO3 write the forward and reverse reactions

cupoosta [38]

2SO2(g) + O2(g) ---> 2SO3(g) • 2SO2(g) + O2(g) <--- 2SO3(g) • 2SO2(g) + O2(g) <---> 2SO3(g) • 2SO2(g) + O2(g) <--->> 2SO3(g) • Note: The rate of change reaches an equilibrium. The concentration of reactants and products is not equa

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2 years ago

Explain why Cl, is an element and NOT a compound.

GarryVolchara [31]

Answer:

Cl is not a compound because compounds are made up of atoms from MORE than one element. Since Cl is a singular element is cannot be a compound

Explanation:

Just think of it as Compounds are always more than one elements are always Single

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2 years ago

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