The mass of aluminium foil is calculated as follows
mass = density x volume
density = 2.70 g/cm^3
volume 54 cm^3
mass of aluminium foil is therefore = 2.70 g/cm^3 x 54 cm^3 =145.8 grams
cm^3 cancel out each other
A coefficient is a whole number that appears before the formula in an equation.
Answer:
Becuase they can go through mountains and hills, they curve of of those.
The answer is: Nucleus (same as in plant cells)
<span>63.4 g/mol
First, let's determine how many atoms per unit cell in face-centered cubic.
There is 8 corners, each of which has 1 atom, and each of those atoms is shared between 8 other unit cells. So 8*1/8 = 1 atom per unit cell. Additionally, there are 6 faces, each of which has 1 atom that's shared between 2 unit cells. So 6*1/2 = 3 atoms per unit cell. So each unit cell has the mass of 1+3 = 4 atoms.
Since there is 1000 liters per cubic meter, the mass per liter is 8920 kg/1000 = 8.920 kg/L. Now the mass per unit cell is 8920 g * 4.72x10^-26 = 4.21024x10^-22 g per unit cell. The mass per atom is 4.21024x10^-22 g / 4 = 1.05256x10^-22 g/atom, Finally, multiply by Avogadro's number, getting 1.05256x10^-22 g/atom * 6.0221409x10^23 atom/mol = 63.38664625704 g/mol.
Rounding to 3 significant digits gives 63.4 g/mol.</span>
