Let speed of the boat in still water = x miles per hour
Let speed of the current = y miles per hour
When water and current both flow in same direction then effective speed will be sum of both speeds that is (x+y)
now plug the given values in formula speed=distance/time
we get equation:
(x+y)=160/8
or x+y=20...(i)
When water and current both flow in opposite direction then effective speed will be difference of both speeds that is (x-y)
now plug the given values in formula speed=distance/time
we get equation:
(x-y)=160/40
or x-y=4
or x=4+y...(ii)
plug value of x into (i)
4+y+y=20
4+2y=20
2y=16
y=8
plug value of y into (ii)
x=4+8=12
Hence final answer is given by:
Speed of the boat in still water = 12 miles per hour
Speed of the current = 8 miles per hour
Answer:
Bots are very annoying and they post inappropriate content too
Step-by-step explanation:
They need to be stopped
Answer:
y=5/3 is the only real solution
Step-by-step explanation:
Solve for y over the real numbers:
11 y^2 - 19 y - 10 = -4 y^2
Add 4 y^2 to both sides:
15 y^2 - 19 y - 10 = 0
The left hand side factors into a product with two terms:
(3 y - 5) (5 y + 2) = 0
Split into two equations:
3 y - 5 = 0 or 5 y + 2 = 0
Add 5 to both sides:
3 y = 5 or 5 y + 2 = 0
Divide both sides by 3:
y = 5/3 or 5 y + 2 = 0
Subtract 2 from both sides:
y = 5/3 or 5 y = -2
Divide both sides by 5:
Answer: |
| y = 5/3 or y = -2/5
Answer:
692.5
Step-by-step explanation:
