Ask question

Ask question

All categories

3 years ago

11

How many ways are there to choose a committee of 3 people from a group of 5 people? A. 10 B. 12 C. 60 D. 70

1 answer:

kolezko [41]3 years ago

3 0

12 12 12 12 12 12 12 its 12

You might be interested in

Which expression can be used to find the volume

butalik [34]

Well the volume of the cylinder will be equal area of base time height

V = pi(4)^2 *(12)

The formula for the volume of a sphere is V = 4/3 πr³.

7 0

3 years ago

Find the greatest common factor of 20c^2 and 12w

irga5000 [103]

Answer:

60c

Step-by-step explanation:

12x6

10x6

hope i helped bud! ;)

3 0

3 years ago

Bumek [7]

Answer:

A:triangular prism?!!

5 0

3 years ago

Change the following percents to fractions and reduce

Serga [27]

Here are the answers.

6. 63/100

7. 75/100 = 3/4

8. 91/100

9. 18/100 = 9/50

10. 3/100

11. 25/100 = 1/4

12. 5/100 = 1/20

13. 16/100 = 4/25

14. 1/100

15. 79/100

16. 40/100 or 4/10 = 2/5

17. 99/100

18. 30/100 or 3/10 = 3/10

19. 15/100 = 3/20

20. 84/100 = 21/25

I hope you find this answer the most helpful! :)

4 0

3 years ago

Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

<u>iii) Add the volume of the two frustrums</u>

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago