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Nina [5.8K]
3 years ago
5

(23.01) In a randomized comparative experiment on the effect of dietary calcium on blood pressure, researchers divided 58 health

y white males at random into two groups. One group received calcium; the other, a placebo. At the beginning of the study, the researchers measured many variables on the subjects. The paper reporting the study gives x⎯⎯⎯=113.7 and s = 9.1 for the seated systolic blood pressure of the 29 members of the placebo group. Give a 96% confidence interval for the mean blood pressure in the population from which the subjects were recruited is.
Mathematics
1 answer:
Paul [167]3 years ago
5 0

Answer:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

Step-by-step explanation:

Information given

\bar X=113.7 represent the sample mean

\mu population mean (variable of interest)

s=9.1 represent the sample standard deviation

n=29 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=29-1=28

The Confidence is 0.96 or 96%, the significance is \alpha=0.04 and \alpha/2 =0.02, and the critical value would be t_{\alpha/2}=2.154

Replacing the info we got:

113.7-2.154\frac{9.1}{\sqrt{29}}=110.06    

113.7+2.154\frac{9.1}{\sqrt{29}}=117.34    

And the 96% confidence is given by (110.06; 117.34)

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