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Alecsey [184]
2 years ago
10

Edhesive 6.8 lesson practice answers

Computers and Technology
1 answer:
FromTheMoon [43]2 years ago
6 0

Answer:

1.) 25 ; 15 ; 15

2.) 50 ; 15 ; 50

Explanation:

In the first function written :

The variable val was initially decaled or assigned a value of 25 and that was what was printed first.

However, after the example function was written, the val variable was finally assiagned a value of 15 within the function. However, it was also declared that the global variable takes uonthe val value. Hence, the val variable initially assigned a value, of 25 changes to 15 globally.

For the second code :

From the top:

Val was assigned a value of 50 ;

Hence,

print(val) gives an output of 50

Within the function definition which prints the value of val that is assigned a value of 25 within the function.

Since tbe global variable isnt reset.

Printing Val again outputs 50;since ito is outside the function.

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   private double width;

   private double heigth;

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       System.out.println("The Width of Rectangle 1 is: "+rectangle1.getWidth());

       System.out.println("The Perimeter of Rectangle 1 is: "+rectangle1.perimeter(4,40));

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       // Second Rectangle object

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       System.out.println("The Width of Rectangle 2 is: "+rectangle2.getWidth());

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   }

}

Explanation:

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  • Then a RectangleTest class containing a main method is created and two Rectangle objects are created (Follow teh comments in the code)
  • Methods to get height, width, area and perimeter are called on each rectangle object to print the appropriate value
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