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Alecsey [184]
3 years ago
10

Edhesive 6.8 lesson practice answers

Computers and Technology
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

1.) 25 ; 15 ; 15

2.) 50 ; 15 ; 50

Explanation:

In the first function written :

The variable val was initially decaled or assigned a value of 25 and that was what was printed first.

However, after the example function was written, the val variable was finally assiagned a value of 15 within the function. However, it was also declared that the global variable takes uonthe val value. Hence, the val variable initially assigned a value, of 25 changes to 15 globally.

For the second code :

From the top:

Val was assigned a value of 50 ;

Hence,

print(val) gives an output of 50

Within the function definition which prints the value of val that is assigned a value of 25 within the function.

Since tbe global variable isnt reset.

Printing Val again outputs 50;since ito is outside the function.

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Answer:

The correct answer to the following question will be "Semantic and Syntax error".

Explanation:

<u>Syntax error: </u>

Corresponds to such a mistake in a pattern sentence structure that is composed in either a specific language of that same coding. Because computer programs have to maintain strict syntax to execute appropriately, any elements of code that would not adhere to the programming or scripting language syntax can result inside a syntax error.

<u>Semantic error: </u>

That would be a logical error. This is because of erroneous logical statements. Write inaccurate logic or code of a program, which results incorrectly whenever the directives are implemented.

So, it's the right answer.

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Assume you are given three variables, revenue, expenses, and profit, all of type Money (a structured type with two int fields, d
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Answer:

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}

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profit.cents = revenue.cents - expenses.cents;

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Explanation:

We know that profit is given as: revenue - expenses from the question.

From the given expression above;

if(revenue.cents - expenses.cents < 0)

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else the profit.dollars and the profit.cent is computed directly without needing to carry over:

profit.dollars = revenue.dollars - expenses.dollars;

profit.cents = revenue.cents - expenses.cents;

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3 years ago
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Answer:

Try and do number = 7

If that does not work then I dont know what to tell you.

Explanation:

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Answer:

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