Recall the secant-tangent theorem, and you have
EA^2 = EC*CD
12^2 = 8*(x+10)
and now ED = EC+CD = 8+x+10
I suspect a typo somewhere in the murk above
Answer:
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Step-by-step explanation:
Answer:
1. Locate the y-intercept on the graph and plot the point.
2. From this point, use the slope to find a second point and plot it.
3. Draw the line that connects the two points.
Answer: 12 h + 135
Step-by-step explanation: 7h +135 + 5h = ?h + ?
7h +5h +135
=12h +135
So u combine like terms together which are 7h and 5h which gives you 12 h.And then you have 135 left,so you add 12h to 135.
Ps.If you don't know what like terms are.I will explain down below.
Like terms are variable that are the same.For an example 4y and 3y are like terms .Another example is 1/3 xy and 6xy .
Hope this helps :) and if it does please give brainliest .
Add all the like terms together so 4x-3x is x or 1x -3y-y is -4y 2z+3z is 5z so put them all together it's x-4y+5z
