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meriva
3 years ago
8

Which number is the best approximation for π/3 : 1, 1.03, 1.05, or 1.07?​

Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

1,05

Step-by-step explanation:

Karolina [17]3 years ago
3 0

9514 1404 393

Answer:

  1.05

Step-by-step explanation:

The relative errors are ...

  • 1 : -4.5%
  • 1.03 : -1.6%
  • 1.05 : +0.3%
  • 1.07 : +2.2%

Of these choices, the best approximation is 1.05.

_____

A very good rational approximation of π is 355/113, which has a relative error of about 0.0000085%. This makes 355/339 a good approximation of π/3.

The relative error in the value n is ...

  (3n/π -1) × 100%

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Which of the following is a factor of 64x^3 +343
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Answer:

(4x + 7) or

(16x^2 - 28x + 49)

Step-by-step explanation:

This is the sum of cubes. If you have choices you really should list them because often the way  we write  answers is not in agreement with what you are given.

Step One

Factor 64x^3  and 343 into prime factors.

64x^3: 4*4*4*x * x *x

343: 7 * 7 * 7

Step Two

Factor using the sum of cubes.

(4x + 7)([4x]^2 - 7*4x + 7^2)

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Defferentiate expression to rational expression​
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Step-by-step explanation:

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A fair coin is tossed three times and the events A, B, and C are defined as follows: A: \{ At least one head is observed \} B: \
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Answer:

a) P(A)=0.875

b) \text{P(A or B)}=0.875

c) \text{P((not A)  or B  or (not C))}=0.625

Step-by-step explanation:

Given : A fair coin is tossed three times and the events A, B, and C are defined as follows: A: At least one head is observed, B: At least two heads are observed, C: The number of heads observed is odd.

To find : The following probabilities by summing the probabilities of the appropriate sample points ?

Solution :

The sample space is

S={HHH,HHT,HTT,HTH,TTT,TTH,THH,THT}

n(S)=8

A: At least one head is observed

i.e. A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

n(A)=7

B: At least two heads are observed

i.e. B={HHH,HTT,TTH,THT}

n(B)=4

C: The number of heads observed is odd.

i.e. C={HHH,HTT,THT,TTH}

n(c)=4

a) Probability of A, P(A)

P(A)=\frac{n(A)}{n(S)}

P(A)=\frac{7}{8}

P(A)=0.875

b) P(A or B)

Using formula,

\text{P(A or B)}=P(A)+P(B)-\text{P(A and B)}

\text{P(A or B)}=\frac{n(A)}{n(S)}+\frac{n(B)}{n(S)}-\frac{\text{n(A and B)}}{n(S)}

\text{P(A or B)}=\frac{7}{8}+\frac{4}{8}-\frac{4}{8}

\text{P(A or B)}=\frac{7}{8}

\text{P(A or B)}=0.875

(c) P((not A)  or B  or (not C))

A={HHH,HHT,HTT,HTH,TTH,TTH,THH,THT}

not A = {TTT} = 1

B={HHH,HTT,TTH,THT}

C={HHH,HTT,THT,TTH}

not C = {HHT,HTH,THH,TTT} = 4

So, not A or B or not C = {HHH,HHT,HTH,THH,TTT}=5

\text{P((not A)  or B  or (not C))}=\frac{5}{8}

\text{P((not A)  or B  or (not C))}=0.625

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Step-by-step explanation:

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