Answer: 1
/2 (
x
2 − 16
x + 6
)
Step-by-step explanation:
Answer:
A)$ 45
B) $105
Step-by-step explanation:
Bag and a belt cost $255
Let bag = x
Let belt = y
X+y= 255 equation 1
Let total money be z first
Remaining money= z-255
X-30 = z-255
Y +15 = z-255
Equating the left side of the equation
X+30 = y+15
X-y= 45 equation 2
Solving simultaneously
X+y= 255
X-y= 45
2x = 300
X= 150
If x= 150
150-y= 45
150-45= y
105=y
Bag = $150
Belt = $105
Bag Is 150-105 more than the belt
150-105= $45
The least common multiple of 30 and 13 is 390 !
Answers:
If an angle is labeled with a single letter, that letter represents the <u> vertex </u> of the angle.
If more than one angle has the same vertex, you must use <u> 3 </u> points to name the angle. The <u> </u><u>middle </u> point named must be the vertex.
=================================================================
Explanation:
If we have a single triangle, and no other extra lines, then we can use single letters to name the three angles. Each vertex of the triangle corresponds to the vertex of that angle.
If you were to draw many triangles, in which some may or may not overlap, you'll mostly likely need to name the angle using 3 letters. This is so you are very specific about which angle you're talking about. The middle letter is always the vertex. The left and right letters are points on the arms of the angle. The order of the left and right letters doesn't matter as long as the middle letter stays the same. So something like angle ABC is the same as angle CBA.
Answer:
Ix - 950°C I ≤ 250°C
Step-by-step explanation:
We are told that the temperature may vary from 700 degrees Celsius to 1200 degrees Celsius.
And that this temperature is x.
This means that the minimum value of x is 700°C while maximum of x is 1200 °C
Let's find the average of the two temperature limits given:
x_avg = (700 + 1200)/2 =
x_avg = 1900/2
x_avg = 950 °C
Now let's find the distance between the average and either maximum or minimum.
d_avg = (1200 - 700)/2
d_avg = 500/2
d_avg = 250°C.
Now absolute value equation will be in the form of;
Ix - x_avgI ≤ d_avg
Thus;
Ix - 950°C I ≤ 250°C