The diamond shape is formed when you graph these coordinates.
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
(–2) + 6 + 1 = 1 + 6 + (–2) is B.Commutative Property
Answer:
(a)3
(b)4
(c)6
(d)5
Step-by-step explanation:
(a)Josie rolls a six-sided die 18 times.
P(she rolls a two)=1/6
Therefore, the estimated number of times she rolls a two in 18 trials
=1/6 X 18
=3
(b)Slips of paper are numbered 1 through 10.
P(the number 10 appear)=1/10
If one slip is drawn and replaced 40 times, expected number of 10
=1/10 X 40
=4
(c)A spinner consists of 10 equal- sized spaces: 2 red, 3 black, and 5 white.
P(red)=2/10
If the spinner is spun 30 times, expected number of red space
=2/10 X 30
=6
(d)A card is picked from a standard deck
P(drawing an ace)=4/52
If the card is picked 65 times and replaced each time.
Expected Number of Aces =4/52 X 65 =5
