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Andrej [43]
3 years ago
13

What are rational numbers​

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer:

In mathematics, a rational number is a number that can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q. Since q may be equal to 1, every integer is a rational number.

IrinaK [193]3 years ago
4 0

Answer:

A number that can be written as a ration of two integers, but neither number can be 0.

Step-by-step explanation:

Example: • 1/2 is a rational number (1 divided by 2, or the ratio of 1 to 2) • 0.75 is a rational number (3/4).

Hope this helps!

Plz name brainliest if possible!

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Gre4nikov [31]
The formula of the midpoint of HE:
\left(\dfrac{x_H+x_E}{2};\ \dfrac{y_H+y_E}{2}\right)

We have H(0; 0) and E(2a; 2a). Substitute:
\left(\dfrac{0+2a}{2};\ \dfrac{0+2a}{2}\right)=(a;\ a)

4 0
3 years ago
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You start driving north for 12 miles, turn right, and drive east for another 16 miles. At
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Answer:

A^2+B^2=C^2

Step-by-step explanation:

12=a

16=b

this is the pythagoreon theorem

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3 years ago
Sharif likes exersicing.He goes hill-climbing every 12 days anf goes swimming every 8 days.If je goes hill-climbing and swimming
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This is a lowest common multiple question.
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4 years ago
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The fuel efficiency (mpg rating) for cars has been increasing steadily since 1980. The formula for a car's fuel efficiency for a
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Answer:

a) In the interval of [1980,1983].

b) In the interval of [1991, 1996].

Step-by-step explanation:

Fuel efficiency:

The fuel efficiency, for the cars, in x years after 1980, is given by:

E(x) = 0.36x + 15.9

15.9 is the fuel efficiency in 1980.

a. In what years was the average fuel efficiency for cars less than 17 mpg (in interval form)?

From 1980 to:

E(x) < 17

0.36x + 15.9 < 17

0.36x < 1.1

x < \frac{1.1}{0.36}

x < 3.06

3.06 = 1980 + 3 = 1983. So

In the interval of [1980,1983].

b. In what years was the average fuel efficiency for cars more than 20 mpg (in interval form)?

From x until 1996.

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0.36x + 15.9 > 20

0.36x > 4.1

x > \frac{4.1}{0.36}

x > 11.38

11.38 = 1980 + 11 = 1991. So

In the interval of [1991, 1996].

4 0
3 years ago
Employer A is offering you a position for $350000 per year l. Employer B is offering the same job for $18.00 per hour. Assuming
ss7ja [257]

Answer:

Depends

Step-by-step explanation:

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5 0
3 years ago
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