Answer:
56.52 units² or 18π units²
Step-by-step explanation:
The formula for the area of a sector is:
A = πr²(x/360°)
where r is the radius and x is the measure of the central angle
Let's substitute the given measures into this equation:
A = πr²(x/360°)
A = (3.14)(12²)(45/360)
Solve:
A = (3.14)(12²)(45/360)
A = (3.14)(144)(45/360)
A = (452.16)(45/360)
A = (452.16)(.125)
A = 56.52
Therefore, the area of the sector is 56.52 units² or 18π units²
Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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I must assume that your graph is that of a straight line, and that the end points of the line are P and B, and (finally) that T is between P and B. If these assumptions are correct, then the length of the line segment PB connecting points P and B is 15 + 10, or 25.
Answer:
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
Step-by-step explanation:
Parallel lines have same slopes.
Line 1, L1: 5x-2y=20 is in standard form Ax+By=C therefore slope m1= -A/B = -5/-2 = 5/2 or you can solve it for y so you will have the equation in slope-intercept form.
5x-2y = 20
-2y = -5x+20
y = (-5/-2)x+20/(-2)
y = (5/2)x-10 hence m1=5/2 and y-intercept is -10
Line 2 , L2: y-y1 = m (x-x1), m=m2=m1=5/2
Point p(5,0) or p(x1,y1) therefore x1=5 , y1=0 and m=5/2
L2: y-0 = 5/2(x-5)
y = 5/2x-25/2
