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3 years ago

Which option has the same median and mode? 1,2,1,3,4 3,4,3,5,6 6,6,7,9,8 9,9,9,2,2

Mathematics

2 answers:

klio [65]3 years ago

7 0

Answer:

Step-by-step explanation:

sweet-ann [11.9K]3 years ago

3 0

Answer:

The last option → 9,9,9,2,2

Step-by-step explanation:

The median or middle number is 9.

The number that occurs the most often is also 9.

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Y=-x+5 solve for. X

vagabundo [1.1K]

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3 years ago

According to a study, 91% of all adults have a cell phone. An employee of a cell phone company attends a community event and has

umka2103 [35]

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Step-by-step explanation:

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3 years ago

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4 years ago

Consider the sets A = fa; b; c; ; ; ; 1; 2; 3g, B = f ; ; ; ; ; g , C = f1; 2; 3; 4; 5; 6g and D = fa; b; cg. (a) List the eleme

Ilya [14]

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hsad

Step-by-step explanation:

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3 years ago

Two boys and three girls are auditioning to play the piano for a school production. Two students will be chosen, one as the pian

finlep [7]

Answer:

30% is the correct answer.

Step-by-step explanation:

Total number of boys = 2

Total number of girls = 3

Total number of students = 5

To find:

Probability that the pianist will be a boy and the alternate will be a girl?

Solution:

Here we have to make 2 choices.

1st choice has to be boy (pianist) and 2nd choice has to be girl (alternate).

$\bold{\text{Required probability }= P(\text{boy as pianist first}) \times P(\text{girl as alternate})}$

Formula for probability of an event E is given as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

For $P(\text{boy as pianist})$ , number of favorable cases are 2 (total number of boys).

Total number of cases = Total number of students i.e. 5

So, $P(\text{boy as pianist})$ is:

$P(\text{boy as pianist}) = \dfrac{2}{5}$

For $P(\text{girl as alternate})$ , number of favorable cases are 3 (total number of girls).

Now, one boy is already chosen as pianist so Total number of cases = Total number of students left i.e. (5 - 1) = 4

$P(\text{girl as alternate}) = \dfrac{3}{4}$

So, the required probability is:

$\text{Required probability } = \dfrac{2}{5}\times \dfrac{3}{4} = \dfrac{3}{10} = \bold{30\%}$

6 0

4 years ago