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Stells [14]
2 years ago
11

Solve the system of linear equations. y = x + 3 y = 2x - 2

Mathematics
2 answers:
PSYCHO15rus [73]2 years ago
7 0

Answer:

x = 5

y = 8

Step-by-step explanation:

to solve the linear system of equation , we would say that let

y = x + 3................................. equation 1  

y = 2x - 2 ............................................. equation 2

substitute for equation 1 into equation 2

we have

x + 3 = 2x -2

collect the like terms

x + 3 + 2 = 2x

x + 5 = 2x

5 = 2x -x

5 = x

x = 5

substitute for the value of x = 5 in equation 2

y = 2x - 2 ............................................. equation 2

y = 2(5) - 2

y = 10 - 2

y = 8

Therefore the value of x and y in the linear equation is 5 and 8 respectively

AlekseyPX2 years ago
5 0

Answer:

x=5, y=8

Step-by-step explanation:

Since both equations equal y, we can set them equal

y = x + 3

y = 2x - 2

x+3 = 2x-2

Subtract x from each side

x-x+3 = 2x-x-2

3 = x-2

Add 2 to each side

3+2= x-2+2

5 =x

Now we need to find y

y =x+3

y=5+3

y=8

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The equivalent expression of (q² − r²s) (q⁴ + q²r²s + r⁴s²) is  q⁶  - r⁶s³

<h3>How to factor the expression?</h3>

The expression is given as:

(q² − r²s) (q⁴ + q²r²s + r⁴s²)

Expand the expression

(q² − r²s) (q⁴ + q²r²s + r⁴s²) =  q²(q⁴ + q²r²s + r⁴s²) − r²s(q⁴ + q²r²s + r⁴s²)

Open the brackets

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Evaluate the like terms

(q² − r²s) (q⁴ + q²r²s + r⁴s²) =  q⁶  - r⁶s³

Hence, the equivalent expression of (q² − r²s) (q⁴ + q²r²s + r⁴s²) is  q⁶  - r⁶s³

Read more about expressions at:

brainly.com/question/11994062

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<h3>Complete question</h3>

Factor the expression. (q² − r²s) (q⁴ + q²r²s + r⁴s²)

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Step-by-step explanation:

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