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Stells [14]
3 years ago
11

Solve the system of linear equations. y = x + 3 y = 2x - 2

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0

Answer:

x = 5

y = 8

Step-by-step explanation:

to solve the linear system of equation , we would say that let

y = x + 3................................. equation 1  

y = 2x - 2 ............................................. equation 2

substitute for equation 1 into equation 2

we have

x + 3 = 2x -2

collect the like terms

x + 3 + 2 = 2x

x + 5 = 2x

5 = 2x -x

5 = x

x = 5

substitute for the value of x = 5 in equation 2

y = 2x - 2 ............................................. equation 2

y = 2(5) - 2

y = 10 - 2

y = 8

Therefore the value of x and y in the linear equation is 5 and 8 respectively

AlekseyPX3 years ago
5 0

Answer:

x=5, y=8

Step-by-step explanation:

Since both equations equal y, we can set them equal

y = x + 3

y = 2x - 2

x+3 = 2x-2

Subtract x from each side

x-x+3 = 2x-x-2

3 = x-2

Add 2 to each side

3+2= x-2+2

5 =x

Now we need to find y

y =x+3

y=5+3

y=8

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<h3>Answer:  They're all the same</h3>

====================================================

Reason:

2^6 means we have 6 copies of "2" multiplied out as shown in choice B. That explains how A and B are the same, and we can say

2^6 = (2*2*2)*(2*2*2)

The parenthesis are optional, but I find they're handy to count the '2's easier.

----------------

Now notice that

2^3 = 2*2*2

So,

2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2^3)*(2^3)\\\\2^6 = (2^3)^2\\\\

The last step is possible because we have two copies of 2^3 multiplied together.

This shows that choice C is equivalent to A and B.

-------------------

Lastly,

2^6 = (2*2*2)*(2*2*2)\\\\2^6 = (2*2)*(2*2)*(2*2)\\\\2^6 = (2^2)*(2^2)*(2^2)\\\\2^6 = (2^2)^3\\\\

The jump to the last step is possible because we have three copies of 2^2 multiplied together.

This shows choice D is equivalent to the others.

All four expressions are the same.

They represent different ways to say the same number. That number being 64.

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