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Jace made 3 three pointers and 6 free throws.
3(3) + 6(1) = 15
Free throws = f
Three pointers = t
t(2) = f
t + f = 15
Answer:
8th term of geometric sequence is 312500
Step-by-step explanation:
Given :
and common ratio (r) = 5
We have to find the 8th term of the geometric sequence whose
and common ratio (r) = 5
Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).
......(1)
where
is nth term and a is first term.
For given sequence
a can be find using
and r = 5
Substitute in (1) , we get,
Thus, 8th term of the sequence denoted as 
Substitute n= 8 in (1) , we get,

Thus 8th term of geometric sequence is 312500
Answer:
14.3
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
14^2 + 3^2 = c^2
196 + 9 = c^2
205 = c^2
Take the square root of each side
sqrt(205) = sqrt(c^2)
14.31782106 = c
Rounding to the nearest tenth
14.3 = c