Answer18:
The quadrilateral ABCD is not a parallelogram
Answer19:
The quadrilateral ABCD is a parallelogram
Step-by-step explanation:
For question 18:
Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope is 90 degree
The slope of a line BC:
m=
m=
m=
The slope is zero degree
The slope of a line CD:
m=
m=
m=
The slope is 90 degree
The slope of a line DA:
m=
m=
m=
m=
The slope of the only line AB and CD are the same.
Thus, The quadrilateral ABCD is not a parallelogram
For question 19:
Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)
The slope of a line is given m=
Now,
The slope of a line AB:
m=
m=
m=
The slope of a line BC:
m=
m=
m=
m=3
The slope of a line CD:
m=
m=
m=
The slope of a line DA:
m=
m=
m=3
The slope of the line AB and CD are the same
The slope of the line BC and DA are the same
Thus, The quadrilateral ABCD is a parallelogram
Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>
Answer:
30%
Step-by-step explanation:
Meagan completed 14/20 math problems. 14÷20 is 0.7
So she completed 70% of those math problems. The question is How many does she have left?
So she has 30% left to complete.
ANSWER: I think that the answer is 28.26
Step-by-step explanation:
I did this a while ago. I hope that I helped<3