Answer:
large central vacuole
Explanation:
mature plant cell contains large vacuoles while a animal cell has small vacuoles
The population changed the way it did because the mutation allowed the mutated animals to better survive in their environment compared to the normal species. Their size made them capable of getting food from higher branches that the normal species couldn't reach. THE ANSWER WAS ON GOOGLE
The five major types of estuaries classified by their geology are coastal plain, bar-built, deltas, tectonic and fjords. In geologic time, which is often measured on scales of hundreds of thousands to millions of years, estuaries are often fleeting features of the landscape.
Color patterns can be thought of as mosaics of different-sized, form, brilliant, and colored patches. A number of natural conditions, including ambient light, watercolor, viewing distance, and the visual capabilities of guppies and three of their predators, were used to assess how noticeable guppy color patterns were.
A particular color pattern element (patch reflectance )'s spectrum, the medium's transmission spectrum, and the ambient light spectrum that strikes the patch all interact to determine the light spectrum that reaches the eye's surface (air or water).
The light at distance x from the patch that reaches the eye at any given wavelength, I, is the result: Q(& x) is the photon flux from the patch reaching the eye (patch radiance), and Q(A) is the photon flux of ambient light incident on the patch.
Predation intensity varies spatially with guppy color patterns, which are influenced by the make-up of the predator communities (Endler, 1978). As a result, calculations were made independently for the color patterns of guppies that are unique to three different predator communities.
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160g of O₂ will be required to fully react with 150g of glucose when glucose is broken down in our bodies to produce carbon dioxide and water.
The breakdown of glucose in our bodies can be represented by the following reaction:
C₆H₁₂O₆(s) + 6O₂(g) → 6CO₂(g) + 6H₂O(g)
As shown in the reaction, a mole of glucose reacts with 6 moles of oxygen.
To calculate the molecular mass:
1 mole of glucose (C₆H₁₂O₆) = (6x12) + (12x1) + (6x16) = 180g
6 moles of oxygen= 6x (2x16) = 192g
180g of glucose reacts with 192g of oxygen. So, to calculate the amount of oxygen required to fully react with 150g of glucose=
150 x 192/180 = 160g of oxygen.
Therefore, 160g of oxygen is required to fully react with 150g of glucose.
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