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3 years ago

-3× + 33= -12 ×= whats the answerr

Mathematics

2 answers:

MAXImum [283]3 years ago

8 0

the answer is x=15

-3x+33=-12

-3x=-12-33

-3x=-45

x=-45/-3

x=15

Lena [83]3 years ago

6 0

Answer:

Step-by-step explanation:

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Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

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2 years ago

Which binomials are factors of x^2−3x−54?

denis23 [38]

Correct Options:- A) x-9 and E) x+6

Step by Step Solution:

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Arturiano [62]

Answer:

Lines c and b, f and d (option b)

Step-by-step explanation:

To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -

Option 1:

Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.

Option 2:

All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.

Option 3:

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Option 4:

Lines c and d are both not transversals, thus clearly don't act as transversals to one another.

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3 years ago

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Naddik [55]

5x5x5=125 so it could be x=5

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3 years ago

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3 years ago

-3× + 33= -12 ×= whats the answerr​

-3× + 33= -12 ×= whats the answerr