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3 years ago

Someone help me ASAP!!!!!!

Mathematics

2 answers:

Studentka2010 [4]3 years ago

7 0

Do the area of the triangle then do the area of the other shape but cut off the triangular part and find the area of that too and then add them together.

Ludmilka [50]3 years ago

3 0

I am terrible at math, so I am not completely sure!
Buuuut......I think the answer is A=21

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Describe a pattern in each sequence. what are the next two terms of each sequence ? 2,4,8,16

yan [13]

Answer:

You are mulitplying the last number by two. The next two terms are 32 and 64.

Step-by-step explanation:

8 0

2 years ago

Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

5 0

3 years ago

The graph shows the distribution of the number of text messages young adults send per day. The distribution is approximately Nor

erik [133]

The percentage of young adults send between 128 and 158 text messages per day is; 34%

<h3>How to find the percentage from z-score?</h3>

The distribution is approximately Normal, with a mean of 128 messages and a standard deviation of 30 messages.

We are given;

Sample mean; x' = 158

Population mean; μ = 128

standard deviation; σ = 30

We want to find the area under the curve from x = 248 to x = 158.

where x is the number of text messages sent per day.

To find P(158 < x < 248), we will convert the score x = 158 to its corresponding z score as;

z = (x - μ)/σ

z = (158 - 128)/30

z = 30/30

z = 1

This tells us that the score x = 158 is exactly one standard deviation above the mean μ = 128.

From online p-value from z-score calculator, we have;

P-value = 0.34134 = 34%

Approximately 34% of the the population sends between 128 and 158 text messages per day.

Read more about p-value from z-score at; brainly.com/question/25638875

#SPJ1

4 0

1 year ago

GCF And LCM of 24, 36, 45

faltersainse [42]

Answer:

Step-by-step explanation:

First lets prime factorize each number

24 = 2 x 2 x 2 x 3

36 = 2 x 2 x 3 x 3

45 = 3 x 3 x 5

GCF = 3 (3 is the only common prime number factor in the 3 numbers)

LCM = 2 x 2 x 2 x 3 x 3 x 5

= 24 x 3 x 5

= 72 x 5

= 360

Happy to help :)

4 0

2 years ago

Marvin has two dollars more than twice the amount of money that Kayla has. Write a statement to represent this situation.

Mariulka [41]

The answer is m=2k+2.

3 0

3 years ago