Someone help me ASAP!!!!!!

Mathematics

2 answers:

Studentka2010 [4]4 years ago

7 0

Do the area of the triangle then do the area of the other shape but cut off the triangular part and find the area of that too and then add them together.

Ludmilka [50]4 years ago

3 0

I am terrible at math, so I am not completely sure!
Buuuut......I think the answer is A=21

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Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. x2+3/2x

denis23 [38]

Answer:

The added term needed for that expression to be a square is 9/16.

Step-by-step explanation:

We're provided with two terms, and asked to add an additional term to make this a perfect square. For this to work, the term needs to be a scalar value that is the square of half the coefficient of the second term.

That coefficient is 3/2, so half of that is 3/4, and its square is 9/16.

If we tack that on the end then, we get:

$x^2 + \frac{3x}{2} + \frac{9}{16}\\=(x + \frac{3}{4})^2$

To confirm the answer, let's expand it and see if we get the original expression:

$(x + \frac{3}{4})^2\\= (x + \frac{3}{4})(x + \frac{3}{4})\\= x^1 + \frac{3x}{4} + \frac{3x}{4} + \frac{9}{16}\\= x^2 + \frac{6x}{4} + \frac{9}{16}\\=x^2 + \frac{3x}{2} + \frac{9}{16}$

So 9/16ths is the scalar that needs to be added on the end.

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3 years ago

How many unit cubes would you need to make a model of a rectangular prism that is 4 units long × 3 units wide × 2 units high?

lara [203]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

F:x→(x+1/x+3), x≠3 and g:x→（6/x-2), x≠2, find f²(4) and g²(1/2)

Sveta_85 [38]

Answer:

$f^2(4) = (\frac{25}{49})\\g^2(\frac{1}{2} ) = 16$

Step-by-step explanation:

Here, given:

$f(x) = (\frac{x+1}{x+3} ), g(x) = (\frac{6}{x-2} )$

Now, here to find the values of $f^2(4), g^2(\frac{1}{2})$

As we know: $f^n(x) = (f(x))^n$

Now, substituting x = 4 in f(x):

$f(4) = \frac{4 +1}{4+3} = \frac{5}{7} \\\implies f^4 = (f(4))^2 = (\frac{5}{7} )^2 = \frac{25}{49} \\\implirs f^{(4)} = ( \frac{25}{49})$

Now, substituting x = 1/2 in g(x):

$g(\frac{1}{2} ) = \frac{6}{\frac{1}{2}-2} = \frac{6}{-\frac{3}{2}} \\\\ g(\frac{1}{2} ) = -6\times (\frac{2}{3} ) = -4\\\implies g^2{(\frac{1}{2}) = ( g(\frac{1}{2} ))^2 = (-4 )^2 =16 \\\\\implies g^2{(\frac{1}{2}) = 16$