Answer:
x = 13
Step-by-step explanation:
y=50
50 = 5x - 15
50 + 15 = 5x
65 = 5x
65/5 = 5x/5
13 = x
Answer:
15.2 m
Step-by-step explanation:
You need to draw a figure. Start by drawing a horizontal segment approximately 10 cm long; that is the ground. Label the left end point A and the right endpoint B. On the right endpoint, B, go up a short 1 cm vertically. That is 1.5 m, the height of Zaheer. Label that point C. Now from that point draw a horizontal line that ends up above point A. Label that point D. Now go back to point C. Draw a segment up to the left at a 30 deg angle with CD. End the segment vertically above point D. Label that point E. That is the top of the flagpole. Draw a vertical segment down from point E through point D ending at point A. Segment AE is the flagpole. Go back to point C. Move 3 cm to the left on segment CD, and draw a point there and label it F. That is where Zaheer moved to. Now connect point F to point E. That is a 45-deg elevation to point E, the top of the flagpole.
m<EFD = 45 deg
m<EFC = 135 deg
m<FEC = 15 deg
m<ECD = 30 deg
We now use the law of sines to find EC
(sin 15)/10 = (sin 135)/EC
EC = 27.32
Because of the 30-60-90 triangle, ED = EC/2
ED = 13.66
Now we add the height of Zaheer to find AE.
13.66 + 1.5 = 15.16
Answer: 15.2 m
Answer:
(-6, -4)
Step-by-step explanation:
Use substitution.
Since y is already isolated, substitute it into the y of: 4x+3y=-36.
You should get: 4x+3(x+2)=-36
Simplify this and you'll get:
4x+3x+6=-36
Add both of the variables:
7x+6=-36
Add -6 to both sides, (because there is a -36 on one side, and a 6 on the other, you have to add a negative to eliminate the 6 whilst adding to the -36)
7x=-42
Divide both sides by 7:
x=-6
Now substitute this into y=x+2
y=-6+2
y=-4
The answer is 20 because five times four is 20 so all you do is multiple
Answer:
Angle HGB is equal to Angle FHD because of corresponding angles.
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Corresponding angles normally have an F shape, and it happens when the angles are on the same line, and there are two lines that are parallel to each other.
