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Nata [24]
3 years ago
11

How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c

. 5y + x = −10. 3y + x = 24 d. 5y − x = −10. 3y − x = 24
Mathematics
1 answer:
VMariaS [17]3 years ago
5 0
The answer is d. 5y − x = −10. 3y − x = 24

\frac{1}{5}x-2=  \frac{1}{3}x+8=y
⇒   y= \frac{1}{5}x-2
      y= \frac{1}{3}x+8
________________________
y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}
y= \frac{x}{3} +8= \frac{x}{3} + \frac{24}{3} = \frac{x+24}{3}
________________________
y= \frac{x-10}{5}            ⇒     5y=x-10
y= \frac{x+24}{3}           ⇒     3y=x+24
________________________
5y-x=-10
3y-x=24
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the coordinates of the endpoints of AB are A (-8, -2) and B(16,6). Point P is on AB what are the coordinates of point P such tha
garri49 [273]
We have that
<span>A (-8, -2) and B(16,6)

step 1
find the distance AB in the x coordinates
dABx=(16-(-8))-----> 24 units

step 2
find coordinate x of P (Px)
Px=Ax+(3/5)*dABx------> Px=(-8)+(3/5)*24----> 6.4

step 3
F</span>ind the distance AB in the y coordinates
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step 4
find coordinate y of P (Py)
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see the attached figure

6 0
3 years ago
An arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up
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Answer:

s(t)=-9.8t^2+49t+58.8

Step-by-step explanation:

We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.

We know that equation of an object's height t seconds after the launch is in form s(t)=-gt^2+v_0t+h_0, where

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v_0 = Initial velocity,

h_0 = Initial height.

For our given scenario g=-9.8, v_0=49 and h_0=58.8. Upon substituting these values in object's height function, we will get:

s(t)=-9.8t^2+49t+58.8

Therefore, the function for the height of the arrow would be s(t)=-9.8t^2+49t+58.8.

6 0
3 years ago
Convert (-6, -6) from Cartesian coordinates to polar coordinates. Round the length to the nearest 0.01 Express the
Neko [114]

9514 1404 393

Answer:

  (8.49; 225°)

Step-by-step explanation:

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The magnitude of the vector to the point is its distance from the origin:

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The polar coordinates can be written as (8.49; 225°).

_____

<em>Additional comment</em>

My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.

3 0
2 years ago
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