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elena55 [62]
3 years ago
5

Which ordered pairs are solutions to the inequality x+3y≥−8? Select each correct answer.

Mathematics
2 answers:
valentinak56 [21]3 years ago
6 0

Answer:

A. (-1,-2)

D. (-6,0)

E. (-5,-1)

Step-by-step explanation:

We have been given an inequality x+3y\geq -8. We are asked to find the ordered pairs that are solution to the given inequality.

Let us check each ordered pair by substituting in the given inequality.

A. (-1,-2)

-1+3(-2)\geq -8

-1-6\geq -8

-7\geq -8

Since the given inequality holds true, therefore, ordered pair (-1,-2) is a solution for the inequality.

B. (-16,2)

-16+3(2)\geq -8

-16+6\geq -8

-10\geq -8

Since the given inequality is not true, therefore, ordered pair (-16,2) is not solution for the inequality.

C. (0,-3)

0+3(-3)\geq -8

0-9\geq -8

-9\geq -8

Since the given inequality is not true, therefore, ordered pair (0,-3) is not solution for the inequality.

D. (-6,0)

-6+3(0)\geq -8

-6+0\geq -8

-6\geq -8

Since the given inequality holds true, therefore, ordered pair (-6,0) is a solution for the inequality.

E. (-5,-1)

-5+3(-1)\geq -8

-5-3\geq -8

-8\geq -8

Since the given inequality holds true, therefore, ordered pair (-5,-1) is a solution for the inequality.

andre [41]3 years ago
3 0
<span>x+3.y≥−8

Let x </span>≥ -5 And y ≥ -1 , Then:

(-5) + 3(-1) ≥ -8  . The solution is (-5 , -1)
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A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po
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Answer:

a. See Attachment 1

b. PT = 12.3\ m

c. HT = 31.1\ m

d. OH = 28.4\ m

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OT}{20}

Multiply both sides by 20

20 * tan50 = \frac{OT}{20} * 20

20 * tan50 = OT

20 * 1.1918 = OT

23.836  = OT

OT = 23.836

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

tan30 = \frac{OP}{20}

Multiply both sides by 20

20 * tan30 = \frac{OP}{20} * 20

20 * tan30 = OP

20 * 0.5774= OP

11.548 = OP

OP = 11.548

PT = OT - OP

PT = 23.836 - 11.548

PT = 12.288

PT = 12.3\ m (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

HT^2 = OT^2 + OH^2

Substitute 20 for OH and OT = 23.836

HT^2 = 20^2 + 23.836^2

HT^2 = 400 + 568.154896

HT^2 = 968.154896

Take Square Root of both sides

HT = \sqrt{968.154896}

HT = 31.1\ m <em>(Approximated)</em>

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

tan50 = \frac{OH}{OT}

Multiply both sides by OT

OT * tan50 = \frac{OH}{OT} * OT

OT * tan50 = {OH

OT * 1.1918 = OH

Substitute OT = 23.836

23.836 * 1.1918 = OH

28.4= OH

OH = 28.4\ m<em> (Approximated)</em>

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