All categories

3 years ago

Can someone help me with number 25

Mathematics

1 answer:

gregori [183]3 years ago

8 0

Sure.
The rule says that "The 'n'th term is 2^n + 1. "

You're asked to find the 5th term, so plug '5' into the rule in place of 'n'.

The 5th term = 2^5 + 1

2^5 = 2 x 2 x 2 x 2 x 2 = 32

The 5th term = 32 + 1 = 33 .

You might be interested in

F(x) = x(2x/2)/x(x+5)(x+6)^2 Find the vertical asymptotes?

Alex Ar [27]

Answer:

x = -5, x = -6

Step-by-step explanation:

After canceling common terms from numerator and denominator, there are two factors remaining in the denominator that can become zero. The vertical asymptotes are at those values of x.

$\displaystyle F(x)=\frac{x\frac{2x}{2}}{x(x+5)(x+6)}=\frac{x}{(x+5)(x+6)}$

The denominator will be zero when ...

x + 5 = 0 . . . . at x = -5

x + 6 = 0 . . . . at x = -6

7 0

3 years ago

Papa johns has a pizza whose circumference is 16 Pi. What is the area of the pizza

gulaghasi [49]

The area of the pizza is 20.37.

Hope this helps ^^

8 0

3 years ago

A cylindrical pressure has a height of 9 feet and diameter of 6 feet. How much gas can the pressure vessel hold when full?

AleksAgata [21]

Answer:

81π ft³

Step-by-step explanation:

If the diameter is 6 ft, the radius is 3 ft.

The volume is V = (area of base)(height).

Here, V = (π[3 ft]²)(9 ft) = 81π ft³

3 0

3 years ago

Read 2 more answers

Help me on this math please

FromTheMoon [43]

The correct answer is D

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%284%20%2B%206i%29%20%7B%7D%5E%7B2%7D%20" id="TexFormula1" title="(4 + 6i) {}^{2} " alt="(4 +

34kurt

Answer:

$36i^{2}+48i+16$

Step-by-step explanation:

$(4+6i)^{2}$ is essentially $(4+6i)(4+6i)$ (you are squaring $(4+6i)$ , so multiplying it by itself), so to simplify, you would need to distribute.

A good way to go about this is using the F.O.I.L. method, multiplying the First numbers in the parentheses, then the Outers, then Inners, and finally, Lasts.

$(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$ >> $(4+6i)(4+6i)$

( $(4*4)+(4*6i)+(6i*4)(6i*6i)$ )

After doing so, you would end up with $16+24i+24i+36i^{2}$ , and after combining like terms, $16+48i+36i^{2}$ .

To write the expression in standard form, though, just order the terms from highest to lowest power!

5 0

3 years ago