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2 years ago

On a blueprint, the bedroom wall is 6 in long. the scale factor is 1 to 24. what is the length of the actual wall?

Mathematics

2 answers:

andrezito [222]2 years ago

6 0

Answer:

Hope This Helps! :)

Vesnalui [34]2 years ago

4 0

Answer:

B. 4 inches

Step-by-step explanation:

(24)(1) / 6 = 4

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A scientist measured the width of a square flake of gold to be7.3 x 10 -4mm what is the area of the flake

irakobra [83]

The area of square flake of gold is $53.29 \times 10^{-8} \mathrm{mm}$

<h3><u>Solution:</u></h3>

Given that width of square flake of gold is $7.3 \times 10^{-4}$ millimeter

To find : Area of square flake

Since gold flake is in shape of square, we can use area of square formula

<em><u>The formula for area of square is given as:</u></em>

$area = s^2$

where "s" is the length of one side

$\begin{array}{l}{\text { Area of a square flake }=\left(7.3 \times 10^{-4}\right) \times\left(7.3 \times 10^{-4}\right)} \\\\ {\text { Area of a square flake }=53.29 \times 10^{8}}\end{array}$

Hence , the calculated area of flake is $53.29 \times 10^{-8} \mathrm{mm}$

7 0

2 years ago

Derive these identities using the addition or subtraction formulas for sine or cosine: sinacosb=(sin(a+b)+sin(a-b))/2

Sergeu [11.5K]

Answer:

The work is in the explanation.

Step-by-step explanation:

The sine addition identity is:

$\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)$ .

The sine difference identity is:

$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

We need to find a way to put some or all of these together to get:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$ .

So I do notice on the right hand side the $\sin(a+b)$ and the $\sin(a-b)$ .

Let's start there then.

There is a plus sign in between them so let's add those together:

$\sin(a+b)+\sin(a-b)$

$=[\sin(a+b)]+[\sin(a-b)]$

$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

$=2\sin(a)\cos(b)+0$

$=2\sin(a)\cos(b)$

So this implies:

$\sin(a+b)+\sin(a-b)=2\sin(a)\cos(b)$

Divide both sides by 2:

$\frac{\sin(a+b)+\sin(a-b)}{2}=\sin(a)\cos(b)$

By the symmetric property we can write:

$\sin(a)\cos(b)=\frac{\sin(a+b)+\sin(a-b)}{2}$

3 0

2 years ago

The length of a rectangle is (x + 2). The

Oksanka [162]

Answer:

Step-by-step explanation:

7 0

3 years ago

Will give brainliest if correct.

Tcecarenko [31]

Answer:

What the question? I don’t see nun

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is the greatest common factor of the numerator and denominator of the rational expression below? 5x-20/x^2-2x-8

OleMash [197]

Factories both equations:
5(x - 4) / (x + 2)(x - 4)

Then take out the common brackets:
5 / x + 2

Minus 2 from both sides:
3 / x

If you are looking for the greatest common factor of the numerator and denominator, the answer would be (x - 4)

8 0

2 years ago