Answer:
Thiamine pyrophosphate (derived from vitamin B1) is a coenzyme required for the activity of pyruvate dehydrogenase enzyme complex.
Explanation:
Pyruvate is the end product of glycolysis. During aerobic cellular respiration, pyruvate is oxidatively decarboxylated into acetyl CoA which in turn enters the Kreb's cycle. Oxidative decarboxylation of pyruvate is carried out by enzyme complex pyruvate dehydrogenase (PDH). The first step is simple decarboxylation and is catalyzed by pyruvate decarboxylase of the PDH complex.
The enzyme pyruvate decarboxylase and has a tightly bound coenzyme, thiamine pyrophosphate. Thiamine pyrophosphate is derived from vitamin B1. Lack of vitamin B1 in the human diet leads to beriberi that is characterized by an increased concentration of pyruvate in blood urine since oxidative decarboxylation cannot occur due to lack of the coenzyme thiamine pyrophosphate.
In water molecule the electrons between the oxygen and the hydrogen are shared, but the sharing is not equal. Oxygen pulls electrons slightly towards itself. Therefore, the electrons are more near the oxygen, making that part of molecule(oxygen part) slightly negative. Since the electrons are not near the hydrogen so, that part of the molecule is slightly positive.
<span>The two sentences that accurately describe the girls' experience with heat transfer are "Camille heats a rock in the campfire for 30 minutes, and then removes it with tongs. She greases the rock and lays the bacon strips directly on it." By heating the rocks in the campfire and laying the bacon on the rocks, the girls transferred the heat from the fire to the rocks, and the heat from the rocks to cook the bacon.</span>
Answer:
A.) Smell is a chemical sense.
B.) Odorant molecules dissolve in mucus before stimulating a receptor
C.) Olfactory receptors have hairs on the apical surface that respond to stimuli
Answer:
2.275% of this population has a diastolic blood pressure less than 60 mmHg
Explanation:
Hello!
Yo have the distribution of the diastolic blood pressure in a certain population. Be X: diastolic blood pressure of an individual, X~N(μ;δ²)
Where
μ= 82mmHg
δ=11 mmHg
You need to calculate the probability of an individual of this population having less than 60mmHg diastolic blood pressure.
Symbolically:
P(X<60)
To obtain the value of probability you need to standardize the value of diastolic pressure so that you can obtain it from the standard normal distribution. The way to standardize the value is to subtract the mean and divide by the standard deviation
Z= (X-μ)/δ~N(0;1)
P(Z<(60-82)/11)
P(Z<-2)= 0.02275
I hope it helps!
