Where does the graph of f(x)=2√-x+2 start?
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Hey there :)
( a - b )( a² + ab + b² )
Let us distribute ( a - b ) into the other
a ( a² ) + a ( ab ) + a ( b² ) - b ( a² ) - b ( ab ) - b ( b² )
a³ + a²b + ab² - a²b - ab² - b³
We can further simplify
a²b - ab² = 0
ab² - ab² = 0
a³ - b³
You can see in the picture which I have attached. It is the 8th formula
( a - b )( a² + ab + b² )
Let us distribute ( a - b ) into the other
a ( a² ) + a ( ab ) + a ( b² ) - b ( a² ) - b ( ab ) - b ( b² )
a³ + a²b + ab² - a²b - ab² - b³
We can further simplify
a²b - ab² = 0
ab² - ab² = 0
a³ - b³
You can see in the picture which I have attached. It is the 8th formula